3 years ago

What do these two changes have in common?

Physics

1 answer:

Maslowich3 years ago

3 0

Both making something

You might be interested in

The space shuttle approaches earth at a speed of 2.89*10^4 km/h when it sends a radio signal to earth 1.00*10^5 km away. The rad

zysi [14]

Answer:

3 secods later

Explanation:

6 0

2 years ago

A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. W

DENIUS [597]

Answer

given,

mass of the drop, m = 0.0014 g

speed of the drop, u = 8.1 m/s

a) Change in momentum is equal to impulse

final velocity of the drop, v = 0 m/s

J = m ( v - u )

J = 0.0014 x 10⁻³ x ( 0 - 8.1 )

J = -1.134 x 10⁻⁵ kg.m/s

impulse of the roof = - J = 1.134 x 10⁻⁵ kg.m/s

b) time, t = 0.37 m s

impact of force = ?

we know

J = F x t

1.134 x 10⁻⁵ = F x 0.37 x 10⁻³

F = 0.031 N

the magnitude of the force of the impact is equal to F = 0.031 N

5 0

3 years ago

What was the hikers average velocity during part c of the hike?

Brrunno [24]

Answer:

6 km/h west

Explanation:

During part c of the hike, the hiker moved 6 km west, and the time was 9.45 am to 10.45 am.

So, we have:

- displacement: d = 6 km west

- time taken: from 9.45 am to 10.45 am = 1 hour

Therefore, the average velocity is given by the ratio between displacement and time taken:

$v=\frac{d}{t}=\frac{6 km}{1 h}=6 km/h$

and the direction is the same as the displacement (west)

6 0

3 years ago

Read 2 more answers

Block 1, of mass m1

musickatia [10]

Answer:

M2=0.52kg

Explanation:

thats rightt

7 0

2 years ago

8. A 3.0 x 10' g nerf projectile is fired from a 1.5 kg nerf gun. If the velocity of the projectile is

tatuchka [14]

Answer:

$v_g=0.2\ m.s^{-1}$

Explanation:

Given:

mass of nerf projectile, $m_p=30\ g=0.03\ kg$

velocity of nerf projectile, $v_p=10\ m.s^{-1}$

mass of the gun, $m_g=1.5\ kg$

Now in this case the collision can be assumed to be perfectly elastic.

<u>For an elastic collision:</u>

$m_p.v_p=m_g.v_g$

where:

$v_g=$ recoil velocity of the gun

$0.03\times 10=1.5\times v_g$

$v_g=0.2\ m.s^{-1}$

4 0

2 years ago