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pishuonlain [190]
3 years ago
14

What is the mass of an object that accelerates at 5 m/s2 when pushed with 100 N?

Physics
1 answer:
dangina [55]3 years ago
7 0

Answer:

the answer is 20g

Explanation:

Data:

acceleration:5m/s2

force:100N

mass:?

solution:

force: mass*acceleration

mass: force divided by acceleration

mass:100/5

mass:20g

or another way of solving it is

force: mass*acceleration

100:mass*5

100/5 : mass

20g:mass

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What forces control the strength of the tides
Colt1911 [192]

Answer:

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).

Explanation:

I hope this helps.

7 0
3 years ago
Read 2 more answers
What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?
sashaice [31]

Answer:

0.75 m³/s

Explanation:

Applying,

Q = vA.................... Equation 1

Where Q = flow rate of the water, v = velocity of the water, A = area of the pipe.

From the question,

Given: v = 2.5 m/s, A = 0.3 m²

Substitute these values into equation 1

Q = 2.5(0.3)

Q = 0.75 m³/s

Hence the flow rate of water in the pipe is 0.75 m³/s

4 0
3 years ago
Which examples are a COMPLETE description of motion? Select ALL that apply.
SIZIF [17.4K]
All of them apply because they all are doing some thing to move
8 0
3 years ago
Two charges are sitting 1.5 m apart with a force of 3 N between them. They are now moved farther apart to 2.25 m and one of the
ANTONII [103]

Answer: 2.37N

Explanation:

According to coulombs law which states that the force of attraction (F) between two charges (q1 and q2) is directly proportional to the product of their charges and inversely proportional to the square of the distance (r) between them. Mathematically,

F = kq1q2/r²

For the first two charges that are sitting 1.5 m apart with a force of 3 N between them, we have

3 = kq1q2/1.5²

3 = kq1q2/2.25

Kq1q2= 6.75... (1)

If the charges are now moved farther apart 2.25 m and one of the charges is increased by a factor of 4. The formula becomes

F2 = k(4q1)q2/2.25² (q1 has been increased by factor of 4)

k(4q1)q2 = 5.06F2 ... (2)

Dividing 2 by 1 we have

k(4q1)q2/kq1q2 = 5.06F2/3

4 = 5.06F2/3

5.06F2 = 12

F2= 12/5.06

F2 = 2.37N

Therefore the magnitude of the new force between the two charges is 2.37N

5 0
4 years ago
When a 72 W light bulb is connected to a 298 V source, what is the current ?
Norma-Jean [14]

the current is 0.24 Amperes

Explanation

power is the amount of energy transferred or converted per unit time, it can be found using the formula

\begin{gathered} P=I*V \\ where\text{ P is the power} \\ I\text{ is the current} \\ V\text{ is the voltage} \end{gathered}

so

Step 1

a)let

\begin{gathered} P=\text{ 72  Watts} \\ V=298\text{  V} \end{gathered}

b) now, replace in the formula and solve for I

\begin{gathered} P=I*V \\ 72\text{ W=I*298 V} \\ divide\text{ both sides by 298 V} \\ \frac{72W}{298\text{ V}}\text{=}\frac{I*298V}{298\text{ V}} \\ 0.24\text{ Amperes=I} \end{gathered}

therefore,the current is 0.24 Amperes

I hope this helps you

6 0
2 years ago
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