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Lady bird [3.3K]
3 years ago
15

What are the common factors of 35 and 60?

Mathematics
1 answer:
Ksivusya [100]3 years ago
3 0
I think it is 5 !!!!!!!!!!!!!!

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Match each pair of points to the equation of the line that is parallel to the line passing through the pointsB(5,2) and C(7,-5)Y
a_sh-v [17]

we will select each points and find equation of line

option-A:

points are B(5,2) and C(7,-5)

x1=5,y1=2 , x2=7 , y2=-5

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-5-2}{7-5}

m=-3.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=-3.5(x-5)

y=\frac{-7}{2}x+\frac{39}{2}...........Answer

option-B:

points are D(11,6) and E(5,9)

x1=11,y1=6 , x2=5 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-6}{5-11}

m=-0.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-6=-0.5(x-11)

y=\frac{-1}{2}x+\frac{23}{2}...........Answer

option-C:

points are F(-7,12) and G(3,-8)

x1=-7,y1=12 , x2=3 , y2=-8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-8-12}{3+7}

m=-2

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-12=-2(x+7)

y=-2x-2...........Answer

option-D:

points are H(4,4) and I(8,9)

x1=4,y1=4 , x2=8 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-4}{8-4}

m=1.25

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-4=1.25(x-4)

y=\frac{5}{4}x-1...........Answer

option-E:

points are J(7,2) and K(-9,8)

x1=7,y1=2 , x2=-9 , y2=8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{8-2}{-9-7}

m=-\frac{3}{8}

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=\frac{3}{8}(x-7)

y=\frac{3}{8}x-\frac{5}{8}...........Answer

option-F:

points are L(5,-7) and M(4,-12)

x1=5,y1=-7 , x2=4 , y2=-12

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-12+7}{4-5}

m=5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y+7=5(x-5)

y=5x-32...........Answer



7 0
3 years ago
Read 2 more answers
The route that Verlonda takes from her house to a store is represented on the grid below. Which ordered pair represents a point
Vadim26 [7]

Answer:

(3.8)

Step-by-step explanation:

Given

See attachment for grid

Required

Which point is on Veronica's path

On the attached grid, I plotted each of the coordinate pair (i.e the given options, A to D) on the grid.

By observation. we can see that:

A is on the vertical line (y intercept)

B is on the second quadrant

C is just few points to the left of the given path

D represents Verlonda's house

<em>Hence, the required coordinate pair is: (3.8)</em>

8 0
3 years ago
Your math teacher gives you an extra credit problem to figure out her age. Half of her age three years
MatroZZZ [7]

Answer:

Teacher is 27 years old

Step-by-step explanation:

(1/2)(t - 3) = (1/3)(t + 9)

multiply by 6 to clear the fraction

3(t - 3) = 2(t + 9)

Distribute

3t - 9 = 2t + 18

Subtract 2t from both sides

t - 9 = 18

Add 9 to both sides

t = 27

Teacher is 27 years old

6 0
3 years ago
1. The sum of two numbers is 90. Their difference is 18. Find the numbers. A(40, 22) B(45, 45) C(36, 54) D(27, 63) E (40, 50) F
Genrish500 [490]

Answer:

36 and 54

Step-by-step explanation:

54-36=18

54+36= 90

3 0
3 years ago
Find the area of the trapezoid. Pls explain and I will mark brainliest.
timama [110]

Answer:

  • B. 191.4 m²

Step-by-step explanation:

Split the trapezoid as pictured below

Find its height and the upper base, then find the area of the trapezoid.

There are 3 pieces, two of them are 45°×45° and 30°×60°×90° triangles

  • The ratio of sides of a 30°×60°×90° triangle is  1 : √3 : 2
  • The legs of a 45x45 triangle are equal

<u>The above mentioned properties give us:</u>

  • h = 16/2 = 8 m
  • b = 8√3 ≈ 13.85 m
  • a = h = 8 m

<u>Now find the area:</u>

  • A = 1/2( 13 + 8 + 13.85 + 13)*8 = 191.4 m²

Correct choice is B

8 0
3 years ago
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