Since mole ratio of magnesium to hydrochloric acid is 1:2, the answer is 1 mole of HCL.
Answer:
2523.23 cal / g
Explanation:
Mass = 6.80g
Temperature increase (T2 - T1) = 2.25
Heat capaity of calorimeter = 32.00kJK-1 = 7.64818 KcalK-1 ( Converting to calories by multiplying by 4.18)
Heat capacity = 7648.18 cal (converting to cal by mutltiplying by 1000)
Heat capacity = Heat Supplied / Temperature rise
Heat Supplied = Heat capacity * Temperature rise
Heat supplied = 7648.18 * 2.25
Heat Supplied = 17208.405 cal
To obtain the per gram value, we divide by the mass.
This gives us; 17208.405 / 6.80 = 2523.23 cal / g
Answer:
un electrón
En la reacción entre el litio y el oxígeno, el litio cede su electrón de valencia al átomo de oxígeno. Como puede verse en la animación de la derecha, dos átomos de litio reaccionan con un átomo de oxígeno. Cada átomo de litio le da un electrón al átomo de oxígeno.
Explanation:
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Answer:
a. NH3 is limiting reactant.
b. 44g of NO
c. 40g of H2O
Explanation:
Based on the reaction:
4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(l)
4 moles of ammonia reacts with 5 moles of oxygen to produces 4 moles of NO and 6 moles of water.
To find limiting reactant we need to find the moles of each reactant and using the balanced equation find which reactant will be ended first. Then, with limiting reactant we can find the moles of each reactant and its mass:
<em>a. </em><em>Moles NH3 -Molar mass. 17.031g/mol-</em>
25g NH3*(1mol/17.031g) = 1.47moles NH3
Moles O2 = 4 moles
For a complete reaction of 4 moles of O2 are required:
4mol O2 * (4mol NH3 / 5mol O2) = 3.2 moles of NH3.
As there are just 1.47 moles, NH3 is limiting reactant
b. Moles NO:
1.47moles NH3 * (4mol NO/4mol NH3) = 1.47mol NO
Mass NO -Molar mass: 30.01g/mol-
1.47mol NO * (30.01g/mol) = 44g of NO
c. Moles H2O:
1.47moles NH3 * (6mol H2O/4mol NH3) = 2.205mol H2O
Mass H2O -Molar mass: 18.01g/mol-
2.205mol H2O * (18.01g/mol) = 40g of H2O
Boiling point of the fragments, for example Ethanol is 78 degrees C, and water is 100.