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zlopas [31]
3 years ago
13

Rs 7.65 + Rs 8.65please solve this for me ​

Mathematics
1 answer:
IgorLugansk [536]3 years ago
8 0

Answer:

16.30

Step-by-step explanation:

It is 16.30 because 8.65+7.65 = 16.30

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october 18

Step-by-step explanation:

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3 years ago
Below is a puzzle that requires algebraic thinking. Choose two numbers to fill in the white boxes in the top row. Follow the arr
kifflom [539]

The computation illustrated shows that the numbers that can be used to get the sum of 42 will be 12 and 15.

<h3>How to compute the value?</h3>

It should be noted that the puzzle simply involves algebraic thinking. The goal is to find numbers that can be added together that will give 42.

From the information, it should be noted that 7 and 8 have been given. Therefore, this will be:

= 42 - (7 + 8)

= 42 - 15

= 27

Therefore, the numbers that can give 27 can be put in the box. An example is 12 and 15.

Learn more about computations on:

brainly.com/question/4658834

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6 0
2 years ago
The radius of the base of the right circular cone shown below is 5 inches and the height of the cone is 7 inches solving which o
kotykmax [81]

Answer:

The required equation is \tan\theta=\dfrac{7}{5}.

Step-by-step explanation:

Consider the provided information.

The required figure is shown below:

It is given that the radius of the base is 5 inches and the height of the cone is 7 inches.

We need to given the equation which gives the measure of \theta.

Now consider the right angle triangle making an angle \theta.

\tan\theta=\frac{\text{Opp}}{\text{Adj}}

\tan\theta=\dfrac{7}{5}

Hence, the required equation is \tan\theta=\dfrac{7}{5}.

6 0
3 years ago
In a right triangle, if the length of one leg is 4 and the length of the hypotenuse is 8, what is the length of other leg, in si
german
Given the pythagorean theorem;
a^2 + b^2 = c^2...

The length of your last leg would be 6.928203230275509

Or "the square root of" 48.
5 0
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Y = 2x – 4 and y = x – 2
hammer [34]

Step-by-step explanation:

x=2

y=0

.................

7 0
3 years ago
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