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2 years ago

Write the perimeter of the floor plan shown as an algebraic expression in x

Mathematics

1 answer:

ziro4ka [17]2 years ago

4 0

From the figure, the perimeter is

P = 11 + (x-2) + (11-3) + [(x-2) - (x-11)] + (x-11)

= 11 + x - 2 + 8 + 9 + x - 11

= 2x + 15

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What's the area of this? PLS HELP

balandron [24]

Answer:

446mm

Step-by-step explanation:

If we box off parts of the area, it makes it easier to solve. I personally broke it into tiny bits:

Upper left box: 16mm

Bigger box (excluding little box): 90mm

Big rectangle: 340mm

Now, add them all together.

Equals 446mm

3 0

2 years ago

Read 2 more answers

Jimmy wants to serve iced tea at his birthday party. He purchases 14 containers filled with 1.5 liters of tea. Approximately how

jenyasd209 [6]

Answer:

5.5 gallons

Step-by-step explanation:

set up a proportion; Liters in numerator and Gallons in denominator

let x = approx number of gallons

21 = 3.8

x 1

3.8x = 21

x = 21 ÷ 3.8

x ≈ 5.5

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2 years ago

Find a recurrence relation for the number of sequences of 1s, 3s, and 5s whose terms sum to n. (b) Repeat part (a) with the adde

Vladimir [108]

Answer:

The solution has been given in the following attachment .

Step-by-step explanation:

3 0

2 years ago

The point K lies on the segment JL.

vlabodo [156]

Answer:

( -9, 5)

Step-by-step explanation:

We can observe that x coordinate increases on line segment JL from J and y coordinate decreases.

The difference in x:

-18 - 3 = -21

The difference in y:

17 - (-11) = 28

Point K is at 3/7 distance from J, so it's coordinates will be:

-18 -(-21*3/7) = -18 + 9 = -9

17 - (28*3/7) = 12- 7 = 5

So K = ( -9, 5)

6 0

3 years ago

The function f(x)=2/3x-4 was replaced with f(x+k)=2/3x-6 what is the value of k

HACTEHA [7]

Answer:

The given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

Step-by-step explanation:

The given function is $f(x)=\frac{2x}{3}-4\hfill (1)$

and when x=x+k then $f(x+k)=\frac{2x}{3}-6\hfill (2)$

Now to find the value of k:

Put x=x+k in the function f(x)

$f(x)=\frac{2x}{3}-4$

$f(x+k)=\frac{2(x+k)}{3}-4$

$f(x+k)=\frac{2x+2k}{3}-4\hfill (3)$

Now comparing equations (2) and (3) we get

$f(x+k)=\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4=\frac{2x}{3}-6$

$\frac{2x+2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2x}{3}+\frac{2k}{3}-4-\frac{2x}{3}+6=0$

$\frac{2k}{3}+2=0$

$\frac{2k}{3}=-2$

$k=\frac{-2\times 3}{2}$

$k=-3$

Therefore k=-3

Therefore the given function $f(x)=\frac{2x}{3}-4$ was replaced with $f(x+k)=\frac{2x}{3}-6$ then the value of k is -3

that is k=-3.

7 0

2 years ago