You deposited a check for $1,200 into your checking account that had a balance of $625 and it "bounced". You had written checks
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Solution:
To test the hypothesis is that the mean ozone level is different from 4.40 parts per million at 1% of significance level.
The null hypothesis and the alternative hypothesis is :
The z-test statistics is :
z = -1.37
The z critical value for the two tailed test at 99% confidence level is from the standard normal table, he z critical value for a two tailed at 99% confidence is 2.57
So the z critical value for a two tailed test at 99% confidence is ± 2.57
Conclusion :
The z values corresponding to the sample statistics falls in the critical region, so the null hypothesis is to be rejected at 1% level of significance. There is a sufficient evidence to indicate that the mean ozone level is different from 4.4 parts per million. The result is statistically significant.
There are 3 feet in 1 yard, that is 3ft/1yd or 1yd/3ft
you can use either, now, in this case, we want to convert
from yards to feet, so, that means we want to cancel out
the yards unit, so we use the form with the "yd" at the bottom
of the fraction, so it cancels out with the one above
you can use either, now, in this case, we want to convert
from yards to feet, so, that means we want to cancel out
the yards unit, so we use the form with the "yd" at the bottom
of the fraction, so it cancels out with the one above