Misty wishes to obtain 85 ounces of a 40% acid solution by combining a 72% acid solution with a 25% acid solution. How much of e
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Answer:
We conclude that the mean scores with uncertified teachers is higher or equal as compared to certified teachers.
Step-by-step explanation:
We are given that reading scores of the students of certified teachers averaged 35.62 points with standard deviation 9.31. The scores of students instructed by uncertified teachers had mean 32.48 points with standard deviation 9.43 points on the same test.
There were 44 students in each group.
Let = <em><u>mean scores with uncertified teachers.</u></em>
= <em><u>mean scores with certified teachers.</u></em>
So, Null Hypothesis, :
{means that the mean scores with uncertified teachers is higher or equal as compared to certified teachers}
Alternate Hypothesis, :
{means that the mean scores with uncertified teachers is lower as compared to certified teachers}
The test statistics that would be used here <u>Two-sample t test statistics</u> as we don't know about the population standard deviations;
T.S. = ~
where, = sample mean scores of students instructed by uncertified teachers = 32.48 points
= sample mean scores of students instructed by certified teachers = 35.62 points
= sample standard deviation of scores of students instructed by uncertified teachers = 9.43 points
= sample standard deviation of scores of students instructed by certified teachers = 9.31 points
= sample of students under uncertified teachers = 44
= sample of students under certified teachers = 44
Also, =
= 9.37
So, <u><em>the test statistics</em></u> = ~
= -1.572
The value of t test statistics is -1.572.
Since, in the question we are not given the level of significance so we assume it to be 5%. <u>Now, at 5% significance level the t table gives critical values of -1.665 at 86 degree of freedom for left-tailed test.</u>
Since our test statistic is more than the critical values of t as -1.572 > -1.665, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u>we fail to reject our null hypothesis</u>.
Therefore, we conclude that the mean scores with uncertified teachers is higher or equal as compared to certified teachers.