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Alexus [3.1K]
3 years ago
12

Which of the following functions is graphed below?

Mathematics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

Step-by-step explanation:-

-

-8239910.76

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Ted borrowed $100 from 2 years at a 10% interest rate. How much interest will he pay on the loan? What will be the total amount
mr_godi [17]

Answer:

Interest = $20

Amount due = $120

Step-by-step explanation:

This is a Simple Interest problem. Simple interest is given as:

I = (P * R * T) / 100

Where I = interest

P = principal or amount loaned

R = rate of interest

T = time elapsed

Ted borrowed $100 from 2 years at a 10% interest rate.

This means that P = $100, R = 10%, T = 2 years.

Hence, the interest will be:

I = (100 * 10 * 2) / 100

I = 2000 / 100

I = $20

The interest after two years will be $20.

Therefore, the total amount due at the end of the loan is:

A = P + I

A = 100 + 20 = $120

The amount due is $120.

5 0
3 years ago
What is the answer for -3x-6xy
Ksenya-84 [330]

Answer:

i dont think this is a real equation.

Step-by-step explanation:

3 0
3 years ago
A table with four legs will sometimes wobble if one leg is shorter than the other three, but a table with three legs will not wo
kaheart [24]
Postulate 3 would be the answer
3 0
3 years ago
Draw a model of 3 <br> sixteen and 2 nines
tensa zangetsu [6.8K]
I can't draw on this thing.. but the way you would do this is draw like 3 groups of 16 little dots and 2 groups of 9 little dots
8 0
3 years ago
Read 2 more answers
Based on a​ survey, assume that ​31% of consumers are comfortable having drones deliver their purchases. Suppose that we want to
CaHeK987 [17]

Answer:

P(X = 2) = 0.3157

Step-by-step explanation:

Let assume that the question wants us to determine the probability that, let say when 5 customers are randomly selected, exactly 2 of the customers are comfortable.

Then;

p = 0.31

n = 5; x = 2

q = 1 - p

= 1 - 0.31

= 0.69

∴

The probability mass function is:

P(X =x) = ^n C_r * p^x *q^{n-x}

P(X =x) = ^5 C_2 * (0.31)^2 *0.69^{5-2}

P(X =2) = \dfrac{5!}{2!(5-2)!} * (0.31)^2 *0.69^{3}

P(X =2) = \dfrac{5!}{2!(3)!} * (0.31)^2 *0.69^{3}

P(X =2) = \dfrac{5*4*3!}{2!(3)!} * (0.31)^2 *0.69^{3}

P(X =2) = \dfrac{5*4}{2!} * (0.31)^2 *0.69^{3}

P(X =2) =10* (0.31)^2 *0.69^{3}

P(X = 2) = 0.3157

3 0
3 years ago
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