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PSYCHO15rus [73]
2 years ago
10

Please help mesimplify

a1" title=" \sqrt{32 - \sqrt{50} } " alt=" \sqrt{32 - \sqrt{50} } " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Mnenie [13.5K]2 years ago
5 0

Answer:

\sqrt{32-5\sqrt{2} }

Step-by-step explanation: I hope it helps :)

\sqrt{32-\sqrt{50} } \\\\simplify \: \sqrt{50} \:to \:5\sqrt{2}  \\\\= \sqrt{32-5\sqrt{2} } \\\\Decimal Form: 4.992888

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Answer:

The slopes are

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Therefore, the equations are equations of <u>  Perpendicular Lines .</u>

Step-by-step explanation:

Given:

y=\dfrac{2}{5}\times x + 1    ......................Equation ( 1 )

5x+2y=-4\\\\\therefore y = \dfrac{-5}{2}\times x-2   ..............Equation ( 2 )

To Find:

Slope of equation 1 = ?

Slope of equation 2 = ?

Solution:

On comparing with slope point form

y=mx+c

Where,

m = Slope

c = y-intercept

We get

Step 1.

Slope of equation 1 = m1 = \dfrac{2}{5}

Step 2.

Slope of equation 1 = m2 = -\dfrac{5}{2}

Step 3.

Product of Slopes = m1 × m2 = \dfrac{2}{5}\times -\dfrac{5}{2}=-1

Product of Slopes = m1 × m2 = -1

Which is the condition for Perpendicular Lines

The slopes are

m1=\dfrac{2}{5},m2=-\dfrac{5}{2}

Therefore, the equations are equations of <u>  Perpendicular Lines . </u>

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