Answer:
y = 3/7x - 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
Slope-Intercept Form: y = mx + b
Step-by-step explanation:
<u>Step 1: Define</u>
Slope <em>m</em> = 3/7
Point (14, 0)
<u>Step 2: Find y-intercept </u><em><u>b</u></em>
- Substitute: 0 = 3/7(14) + b
- Multiply: 0 = 6 + b
- Isolate <em>b</em>: -6 = b
- Rewrite: b = -6
<u>Step 3: Write linear equation</u>
y = 3/7x - 6
Answer:
- Perimeter = 22*sqrt(2)
- Area = 60.5 inches
- D
Step-by-step explanation:
Remark
You need 2 facts.
- A square has 4 equal sides.
- It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.
That means you can use the Pythagorean Theorem.
If one side of a square is a then the 1 after it is a as well.
Formula
- a^2 + a^2 = c^2
- 2a^2 = c^2
Givens
Solution
- 2a^2 = 11^2
- 2a^2 = 121 Divide by 2
- a^2 = 121/2 Take the square root of both sides
- sqrt(a^2) = sqr(121/2)
- a = 11/sqrt(2) Rationalize the denominator
- a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
- a = 11 * sqrt(2) / 2
<em><u>Perimeter</u></em>
P = 4s
- P = 4*11*sqrt(2)/2
- P = 44*sqrt(2)/2
- P = 22*sqrt(2)
You don't need the area. The answer is D
<em><u>Area</u></em>
- Area = s^2
- Area = (11*sqrt(2)/2 ) ^2
- Area = 121 * 2 / 4
- Area = 60.5
Answer:
- domain (-∞, ∞)
- range (-∞, 4]
- increasing (-∞, 0)
- decreasing (0, ∞)
- constant (only at x=0, not on any interval)
Step-by-step explanation:
The graph is of the equation y = -x^2 +4. It is a polynomial of even degree, so has a domain of all real numbers: (-∞, ∞).
The vertical extent of the graph includes y=4 and all numbers less than that:
range: (-∞, 4]
The graph is increasing to the left of its vertex at x=0, decreasing to the right.
increasing (-∞, 0); decreasing (0, ∞)
There is no interval on which the function is constant. It has a horizontal tangent at x=0, but a single point does not constitute an interval.
