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3 years ago

11

A circular pool has a diameter of 24 feet. What is the area of the pool to the nearest tenth

1 answer:

astraxan [27]3 years ago

6 0

Answer:

c) 452.4 square feet

Step-by-step explanation:

HOPE THIS HELPS, MARK AS BRAINLIEST PLEASE NOT THE FILE VIRUS EXPLOITER

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Two more than a certain number is 15 less than twice the number. Find the number

Svetllana [295]

2+x=2x-15
>> 2+15=2x-x
>> 17 = x

So the answer is <u>17</u>

6 0

3 years ago

Read 2 more answers

Figure out the answer to each riddle below:

Ahat [919]

1. 79
2. 330
3. 452
4. 1212
5. 351
6. 202
7. 238

5 0

3 years ago

Robert says the expression 2+3 times 7 and 2+(3 times 7) have the same value. Is Robert correct? Explain your answer and evaluat

erastovalidia [21]

Yes because you multiply first so in this case you multiply 7 and 3 first. Since the second expression is in parenthesis you do that first just like you do 7 times 3. Then you just add 2 to that. The value of both expressions is 23

4 0

3 years ago

What is the solution to 3/4b=8

soldier1979 [14.2K]

Answer:

$b=\frac{32}{3}$

Step-by-step explanation:

$\frac{3}{4}b=8$

Multiply both sides by 4:

$4\times \frac{3}{4}b=8\times4$

$3b=32$

Divide both sides by 3:

$\frac{3b}{3}=\frac{32}{3}$

$b=\frac{32}{3}$

6 0

3 years ago

Suppose a basketball player has made 231 out of 361 free throws. If the player makes the next 2 free throws, I will pay you $31.

statuscvo [17]

Answer:

The expected value of the proposition is of -0.29.

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either the player will make it, or he will miss it. The probability of a player making a free throw is independent of any other free throw, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Suppose a basketball player has made 231 out of 361 free throws.

This means that $p = \frac{231}{361} = 0.6399$

Probability of the player making the next 2 free throws:

This is P(X = 2) when n = 2. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,2}.(0.6399)^{2}.(0.3601)^{0} = 0.4095$

Find the expected value of the proposition:

0.4095 probability of you paying $31(losing $31), which is when the player makes the next 2 free throws.

1 - 0.4059 = 0.5905 probability of you being paid $21(earning $21), which is when the player does not make the next 2 free throws. So

$E = -31*0.4095 + 21*0.5905 = -0.29$

The expected value of the proposition is of -0.29.

3 0

3 years ago