The manager already hired 9 people. Let 
be the number of people he still can hire. Since these people will add to the 9 he already hired, when the hiring campaign will be over he will have hired 
people. We know that he can't hire more than 14 people, so the number of people hired must be less than or equal to 14:
If we subtract 9 from both sides, we have
so, the manager can hire at most 5 other people
Answer:
answer in photo
hope this helps :)
Step-by-step explanation:
Answer:
3/10
Step-by-step explanation:
9-6=3
both fractions have the same denominator so they keep it
9/10 - 6/10 = 3/10
<h3>3/10 is also 0.33</h3>
If we can match teh bases we can solve
because if x=x and xᵃ=xᵇ, we can conclude that a=b
16=2⁴
32=2⁵
rememeber that
2=2 so we conclude that 4(3x+2)=5(-2x-7)
4(3x+2)=5(-2x-7)
expand/distribute
12x+8=-10x-35
add 10x both sides
22x+8=-35
minus 8 both sides
22x=-43
divide both sides by 22
x=-43/22
11. m=5 p=15
12. g=3 k=3
13. b=40
