Answer:are there any abc or do you have to make an answer?
Explanation:
Answer is: formula of hydrate is CoCl₂· 6H₂O -c<span>obalt(II) chloride hexahydrate
</span>m(CoCl₂· xH₂O) = 1,62 g.
m(CoCl₂) = 0,88 g.
n(CoCl₂) = m(CoCl₂) ÷ M(CoCl₂)
n(CoCl₂) = 0,88 g ÷ 130 g/mol
n(CoCl₂) = 0,0068 mol.
m(H₂O) = 1,62 g - 0,88 g.
m(H₂O) = 0,74 g.
n(H₂O) = m(H₂O) ÷ m(H₂O)
n(H₂O) = 0,74 g ÷ 18 g/mol
n(H₂O) = 0,041 mol.
n(CoCl₂) : n(H₂O) = 0,0068 mol : 0,041 mol.
n(CoCl₂) : n(H₂O) = 1 : 6.
Answer:
invalid
Explanation:
Just imagine doing this experiment MULTIPLE TIMES and one of the trials you get 72 Kcal while in another u get 12kcal. It doesn't make sense. Somewhere in the experiment she went wrong. So its invalid
<u>Answer:</u> The concentration of 
ions is 0.10 M and that of 
ions is 0.30 M
<u>Explanation:</u>
We are given:
Concentration of 
= 0.10 M
The chemical equation for the ionization of aluminium bromide follows:
1 mole of aluminium bromide produces 1 mole of aluminium ions and 3 moles of bromide ions
So, concentration of aluminium ions = 0.10 M
Concentration of bromide ions = ![[(3\times 0.1)]=0.3M](https://tex.z-dn.net/?f=%5B%283%5Ctimes%200.1%29%5D%3D0.3M)
Hence, the concentration of ions is 0.10 M and that of ions is 0.30 M
