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3 years ago

Divide 7/24 by 35/48 and reduce the quotient to the lowest fraction

2 answers:

4 0

Given:
1st fraction - 7/24
2nd fraction - 34/48

Rules in dividing fractions:

1) Get the reciprocal of the 2nd fraction.
34/48 becomes 48/34

2) Multiply the 1st fraction to the reciprocal of the 2nd fraction
7/24 * 48/34 = 7*48 / 24*34 = 336/816

3) Simplify the fraction
336/816 ⇒ 112/272 ⇒ 56/136 ⇒ 14/34 ⇒ 7/17

336 ÷ 3 = 112
816 ÷ 3 = 272

112 ÷ 2 =   56
272 ÷ 2 = 136

56 ÷ 4 = 14
136 ÷ 4 =   34

14 ÷ 2 =    7
34 ÷ 2 =   17

7/24 ÷ 35/48 = 7/17

kifflom [539]3 years ago

3 0

7/24 ÷ 35/48

= 7/24 × 48/35. 7 into 35 is 5. 24 into 48 is 2.

= 2/5

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kati45 [8]

Look at the fractions!

9/10 is less than 1.

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3 years ago

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4 - ⅛w < 16<br> can someone plz anwser and show work

padilas [110]

Step-by-step explanation:

so first convert it into an algebraic equation

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2 years ago

otez555 [7]

Answer:

20°

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3 years ago

12-5x-4kx=y solve for x

Lana71 [14]

Hi there!

$12 - 5x - 4kx = y

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3 years ago

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

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3 years ago