Answer:
F=−4c 2 +7c+5
Step-by-step explanation:
Follow the steps
106=x+79+x+45
106=2x+124
-124= -124
-18=2x
( -18)/2=(2x)/2 <----- solving for x
-9=x
then
angle LMF= -9+79
=70
angle FMN= -9+45
= 36
(when you add 70 and 36 together you get 106 which is the measurement of angle LMN or in other word the whole thing)
In conclusion the answer to the problem is:
Angle LMF is equal to 70.
You can solve this by using "similar triangles".
In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.
You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
![\frac{AC}{BC} = \frac{DF}{EF}](https://tex.z-dn.net/?f=%20%5Cfrac%7BAC%7D%7BBC%7D%20%3D%20%20%5Cfrac%7BDF%7D%7BEF%7D%20)
Substitute for the values of AC, BC, DF and EF:
![\frac{x}{4} = \frac{11}{8} \\ \\ 8x = 4 \times 11 \\ \\ x = \frac{44}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7B11%7D%7B8%7D%20%20%5C%5C%20%20%5C%5C%208x%20%3D%204%20%5Ctimes%2011%20%5C%5C%20%20%5C%5C%20x%20%3D%20%20%5Cfrac%7B44%7D%7B8%7D%20)
![x = 5.5 \: units](https://tex.z-dn.net/?f=x%20%3D%205.5%20%5C%3A%20units)
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
![\frac{AB}{BC} = \frac{DE}{EF}](https://tex.z-dn.net/?f=%20%5Cfrac%7BAB%7D%7BBC%7D%20%20%3D%20%20%5Cfrac%7BDE%7D%7BEF%7D%20)
Substitute for the values and solve:
![\frac{3}{4} = \frac{y}{8}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%3D%20%20%5Cfrac%7By%7D%7B8%7D%20)
![4y = 24 \\ \\ y = 6 \: units](https://tex.z-dn.net/?f=4y%20%3D%2024%20%5C%5C%20%20%5C%5C%20y%20%3D%206%20%5C%3A%20units)
We have the value x to be 5.5 units and y to be 6 units.
Answer:
15% increase
Step-by-step explanation:
2750... 10% of that is 275, add 275 to 2750 is 3025. 1% of 2750 is 27.50, you times that by 5, which is 137.50 and add that to 3025 giving you 3162.50, add the 10% with the 5% gives you 15%, that's the increase.
It has one solution.
please see the attached picture for full solution
Hope it helps
Good luck on your assignment...