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Bogdan [553]
4 years ago
7

How do we get the essential amino acids we need

Chemistry
1 answer:
kherson [118]4 years ago
3 0

Answer: through your diet

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4g of sugar is dissolved in 46 g of water calculate the concentration as percent by mass
Lina20 [59]
The  concentration as  %  by  mass  is  calculated as below

mass  of  solute/mass of  solvent x100
mass of  solute(sugar) = 4g
mass of   solvent(water) =46  g

= 4g/  46 g x100 = 8.7%
3 0
3 years ago
Read 2 more answers
Calculate the pH of a buffer solution created by reacting 100 mL of 0.1 M NH3 with 90 mL of 0.1 M HNO3. (Remember, you can find
algol13

This question is asking for the pH of a buffer solution between ammonia and nitric acid, with given volumes and concentrations. At the end, the result turns out to be 10.488.

<h3>Buffers</h3>

In chemistry, buffers are known as substances attempting to hold a relatively constant pH by mixing and acid and a base (weak and strong). In such a way, for the substances given, the first step will be to calculate the consumed moles as they are mixed:

n_{NH_3}=0.1L*0.1mol/L=0.01mol\\\\n_{HNO_3}=0.09L*0.1mol/L=0.009mol

Now, since ammonia is in a greater proportion, one can calculate how much of it is left after being consumed by the nitric acid:

n_{NH_3}^{left}=0.01mol-0.009mol=0.001mol

And its new concentration:

[NH_3]=\frac{0.001mol}{0.1L+0.09L} =0.00526M

Next, with ammonia's ionization:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We set up the equilibrium expression based on ammonia's Kb:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]}

Which can be solved by introducing x and using ammonia's Kb:

1.8x10^{-5}=\frac{x^2}{0.00526M}\\ \\

Then, we solve for x which is also equal to the concentration of ammonium and hydroxide ions in the solution:

x=\sqrt{0.00526*1.8x10^{-5}}=0.000308M

Ultimately, we calculate the pOH and then turn it into pH with:

pOH=-log(0.00308)=3.512\\\\pH=14-3.512=10.488

Learn more about buffers: brainly.com/question/24188850

6 0
2 years ago
Label each statement below as either describing the limit of detection (LOD) or the limit of quantitation (LOQ
Orlov [11]

Answer:

It is the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy - LOQ

The concentration is equal to three times the standard deviation of the signal from the blank divided by the slope of the calibration curve - LOD

The concentration is equal to 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve - LOQ

It is the minimum amount of analyte that produces a signal that is significantly different from the blank - LOD

Explanation:

We define the limit of detection has the lowest amount of analyte that produces a signal that is significantly different from a blank solution ( the absence of the substance). It is calculated as three times the standard deviation of the signal from the blank divided by the slope of the calibration curve.

The limit of quantitation (LOQ) is defined as the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy. It is measured as 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve.

6 0
3 years ago
If it takes 65.3 min for the concentration of a reactant to drop to 20.0% of its initial value in a first-order reaction, what i
Anna007 [38]

65.3 \div 20

equals 3.265

6 0
3 years ago
Explain how the answer is 4 please
Akimi4 [234]
The image is not loading are you sure you uploaded something
4 0
3 years ago
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