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laila [671]
4 years ago
13

Name two elements that have the same properties as calcium (Ca). (4 points)

Chemistry
1 answer:
enyata [817]4 years ago
7 0
 beryllium, magnesium, strontium,barium<span>, and </span><span>radium. </span>
You might be interested in
Write any two reasons that hydrogen is kept in group 1 ​
rodikova [14]

Answer:

《HOPE IT WILL HELP YOU 》

Explanation:

(1) It resembal Alkali metel in some of properties

(2) it alos resemble as the Helogens in its properties

6 0
3 years ago
How much energy is absorbed when 10 grams of gold increases in
ra1l [238]

Answer:

6.45 joules

Explanation:

energy=10×(55-50)×0.129

=1.29×5

=6.45 J

hope this helps

please like and Mark as brainliest

7 0
3 years ago
Sublimation is snow or ice changing to a gas without melting. What must happen to the molecules for this to happen?
expeople1 [14]

Answer:Sublimation is the conversion between the solid and the gaseous phases of matter, with no intermediate liquid stage. For those of us interested in the water cycle, sublimation is most often used to describe the process of snow and ice changing into water vapor in the air without first melting into water.

Explanation:

6 0
3 years ago
N2H4+H2O2 ——&gt; N2+H2O coefficient
const2013 [10]

Answer:

N2H4 + 2H2O2 ---->N2 + 4H2O

Explanation:

N=2            N=2

H=6 ->8      H=2 ->8

O=2 -> 4     O=1 -> 4

Add coefficients to hydrogen peroxide on the left and water on the right, so that there is an equal number of hydrogens and oxygens.

3 0
3 years ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
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