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Klio2033 [76]
4 years ago
15

Physical Science Structures and Properties of Matter Portfolio

Chemistry
1 answer:
daser333 [38]4 years ago
8 0

Answer:

true

Explanation:

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Convert 92.92 g NaOH to moles
user100 [1]

Answer:

It would be 2.323167848877082

Explanation:

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What element behaves MOST like magnesium (Mg)?<br> A) S <br> B) Si <br> C) Sn <br> D) Sr
tatyana61 [14]

Strontium (Sr). Elements in the same group of the periodic table have similar characteristics.

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3 years ago
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Characteristics of matter that do not involve chemically changing a substance are called _____ properties.
Leviafan [203]

Answer:

Physical properties

Explanation:

These properties are the ones that you can observe or collect by your senses, for example the color, the odor, the sound, the texture, etc. In this case the substance is not going to change to a new one, it could be that is changing of state.

4 0
3 years ago
36. Which statement is incorrect in nuclear decay situations of a nucleus? a. Nucleus has too many protrons = a positron emissio
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The second statement
7 0
3 years ago
How many molecules of F2 react with 66.6 g NH3 ? (stoichiometry)
stiks02 [169]
<h3>Answer:</h3>

5.89 × 10^23 molecules of F₂

<h3>Explanation:</h3>

The equation for the reaction between fluorine (F₂) and ammonia (NH₃) is given by;

5F₂ + 2NH₃ → N₂F₄ + 6 HF

We are given 66.6 g NH₃

We are required to determine the number of fluorine molecules

<h3>Step 1: Moles of Ammonia </h3>

Moles = Mass ÷ Molar mass

Molar mass of ammonia = 17.031 g/mol

Moles of NH₃ = 66.6 g ÷ 17.031 g/mol

                      = 3.911 moles

<h3>Step 2: Moles of Fluorine </h3>

From the equation 5 moles of Fluorine reacts with 2 moles of ammonia

Therefore,

Moles of fluorine = Moles of Ammonia × 5/2

                            = 3.911 moles × 5/2

                           = 9.778 moles

<h3>Step 3: Number of molecules of fluorine </h3>

We know that 1 mole of a compound contains number of molecules equivalent to the Avogadro's number, 6.022 × 10^23 molecules

Therefore;

1 mole of F₂ = 6.022 × 10^23 molecules

Thus,

9.778 moles of F₂ = 9.778 moles × 6.022 × 10^23 molecules/mole

                              = 5.89 × 10^23 molecules

Therefore, the number of fluorine molecules needed is 5.89 × 10^23 molecules

5 0
3 years ago
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