Substituents are trans to each other if the appear on opposite sides in the structure. C, E, G, H and K are trans to the bromo substituent.
The substituted cyclohexane compound is shown in the image attached. Two substituents in a compound are trans to each other if they appear on opposite sides of the structure. Cis substituents appear on the same side of the structure.
Considering the structure as shown in the image attached, the substituents that are trans to the bromo substituent are the substituents shown as letters C, E, G, H and K. They lie opposite to the bromo substituent.
Learn more: brainly.com/question/8155254
Answer:
6.05 g
Explanation:
Molarity of a substance , is the number of moles present in a liter of solution .
M = n / V
M = molarity
V = volume of solution in liter ,
n = moles of solute ,
From the question ,
M = 200mM
Since,
1 mM = 10⁻³ M
M = 200 * 10⁻³ M
V = 250 mL
Since,
1 mL = 10⁻³ L
V = 250 * 10⁻³ L
The moles can be calculated , by using the above relation,
M = n / V
Putting the respective values ,
200 * 10⁻³ M = n / 250 * 10⁻³ L
n = 0.05 mol
Moles is denoted by given mass divided by the molecular mass ,
Hence ,
n = w / m
n = moles ,
w = given mass ,
m = molecular mass .
From the question ,
m = 121 g/mol
n = 0.05 mol ( calculated above )
The mass of tri base can be calculated by using the above equation ,
n = w / m
Putting the respective values ,
0.05 mol = w / 121 g/mol
w = 0.05 mol * 121 g/mol
w = 6.05 g
Answer:
The number and the kinds of atoms in the compound
Explanation:
- A chemical formula of a compound contains symbols o the atoms of the elements present in the compound as well as the number of atoms of each element in the form of subscripts.
- Therefore it helps us to know the elements in a compound and the number of atoms in the compounds.
8H⁺ + 5Fe²⁺ + MnO₄⁻ ⇒ Mn²⁺ + 5Fe³⁺ + 4H₂O
<span>
According to the reaction, Fe</span>²⁺ and MnO4⁻<span> have following stoichiometric ratio:
n(</span>Fe²⁺) : n(MnO4⁻) = 5 : 1
n(MnO4⁻) = n(Fe²⁺) / 5
<span>
So, for each mole of </span>Fe²⁺ it is needed 1/5 moles of MnO4⁻.<span>
</span><span>
</span>
