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Mars2501 [29]
3 years ago
5

The following characteristics describe which of these terms? the substance is not uniform in appearance and each part of the mix

ture contains a combination of different ingredients in different ratios.
A. homogeneous mixtures
B. heterogeneous mixtures
C. pure substance
D. solution
Chemistry
2 answers:
Mademuasel [1]3 years ago
6 0

B. heterogeneous mixtures

Katyanochek1 [597]3 years ago
3 0
B. Heterogeneous mixture
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The breaking buffer that we use this week contains 10mM Tris, pH 8.0, 150mM NaCl. The elution buffer is breaking buffer that als
olasank [31]

Answer:

A breakdown of the breaking buffer was first listed with its respective component and their corresponding value; then a table was made for the stock concentrations in which the volume that is being added was determined by using the formula M_1*V_1 = M_2*V_2. It was the addition of these volumes altogether that make up the 0.25 L (i.e 250 mL)  with water

Explanation:

Given data includes:

Tris= 10mM

pH = 8.0

NaCl = 150 mM

Imidazole = 300 mM

In order to make 0.25 L solution buffer ; i.e (250 mL); we have the following component.

Stock Concentration             Volume to be             Final Concentration

                                               added            

1 M Tris                                     2.5 mL                         10 mM

5 M NaCl                                  7.5 mL                        150 mM

1 M Imidazole                           75 mL                         300 mM    

M_1*V_1 = M_2*V_2. is the formula that is used to determine the corresponding volume that is added for each stock concentration

The stock concentration of Tris ( 1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.01 M *250mL\\V_1 = 2.5mL

The stock concentration of NaCl (5 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.15 M *250mL\\V_1 = 7.5mL

The stock concentration of Imidazole (1 M ) is as follows:

M_1*V_1 = M_2*V_2.

1*V_1= 0.03 M *250mL\\V_1 = 75mL

Hence, it is the addition of all the volumes altogether that make up 0.25L (i.e 250 mL) with water.

5 0
3 years ago
Making solutions is an extremely important component to real-life chemistry. If you make 3.00 L of a solution using 90.0 g of so
kumpel [21]

Answer:

Final concentration of NaOH = 0.75 M

Explanation:

For NaOH :-

Given mass = 90.0 g

Molar mass of NaOH = 39.997 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{90.0\ g}{39.997\ g/mol}

Moles\ of\ NaOH= 2.2502\ mol

Molarity is defined as the number of moles present in one liter of the solution. It is basically the ratio of the moles of the solute to the liters of the solution.

The expression for the molarity, according to its definition is shown below as:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Where, Volume must be in Liter.

It is denoted by M.

Given, Volume = 3.00 L

So,

Molarity=\frac{2.2502\ mol}{3.00\ L}=0.75\ M

<u>Final concentration of NaOH = 0.75 M</u>

5 0
3 years ago
Which compound can act as both a Bronsted-Lowry acid and a Bronsted-Lowry base?
Dvinal [7]
The answer is A. Water

Bronsted-Lowry base compounds are those that can accept protons

Bronsted-Lowry Acid Compounds are those that can recieve one

Water / H2O is an Amphoteric compund which mean that its molecul can act as a Base and Acid compound, so the answer is A.
5 0
3 years ago
Pure metals tend to be weaker and more reactive than an alloy which is a
Alex17521 [72]
Alloys are supposed to give greater strength to metals, which is why gold is mixed with others to make it harder. They have greater strength and are more resistant to erosion.
5 0
3 years ago
If 3.5 grams of NaN3 decomposed, how many grams of N2 would be produced?
Wewaii [24]

Answer:

5.25 moles.

Explanation:

The decomposition reaction of NaN₃ is as follows :

2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)

We need to find how many grams of N₂ produced in the process.

From the above balanced chemical reaction, we conclude that the ratio of moles of sodium azide and nitrogen gas are 2 : 3.

2 moles of sodium azide decomposes to give 3 moles of nitrogen gas. So,

3.5 moles of sodium azide decomposes to give \dfrac{3}{2}\times 3.5=5.25 moles of nitrogen gas.

Hence, the number of moles produced is 5.25 moles.

6 0
3 years ago
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