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strojnjashka [21]
3 years ago
11

34. Given the fact that the concentrations of reactants and

Chemistry
1 answer:
Nina [5.8K]3 years ago
3 0

Answer:

The word dynamic is used to describe chemical equilibrium because even though the concentration of reactants and products remains constant, the reaction does not stop, but still continues with the rate of forward reaction equal to the rate of backward reaction. This is opposed to static equilibrium where there is no reaction at all.

Hope this helps you out!

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Calculate the volume of an object that has a mass of 20.00 g and a density of 2.45 g/cm^3.
sveta [45]

Answer:

2450000 gram

Explanation:

v= m × ρ= 1 cubic meter × 2.45 gram/cubic centimeter= 1000000 cubic centimeter × 2.45 gram/cubic centimeter= 2450000 gram

7 0
3 years ago
Read 2 more answers
At a certain temperature and pressure, 0.20 mol of carbon dioxide has a volume of 3.1 L. A 3.1-L sample of hydrogen at the same
Arada [10]

A 3.1 L sample of hydrogen <u>d. contains the same number of molecules</u>

as 3.1 L of carbon dioxide at the same temperature and pressure.

This is the fundamental principle of <em>Avogadro’s hypothesis</em>: equal volume of gases at the same temperature and pressure contain the same number of molecules.

The sample of carbon dioxide has a <em>greater mass</em>, a <em>greater number of atoms</em>, and a <em>greater density</em>, than the sample of hydrogen.  

7 0
3 years ago
How many grams are in 1.2 x 1024 atoms of sodium?
jarptica [38.1K]

Answer:

46 g

Explanation:

First we <u>convert 1.2 x 10²⁴ atoms of sodium into moles</u>, using <em>Avogadro's number</em>:

  • 1.2x10²⁴ atoms ÷ 6.023x10²³ atoms/mol = 2.0 mol

Then we <u>convert 2.0 moles of sodium into grams</u>, using <em>sodium's molar mass</em>:

  • 2.0 mol Na * 23 g/mol = 46 g

Thus, there are 46 grams in 1.2x10²⁴ atoms of sodium.

3 0
3 years ago
What is the quantity of heat (in kJ) associated with cooling 185.5 g of water from 25.60°C to ice at -10.70°C?Heat Capacity of S
Cerrena [4.2K]

Taking into account the definition of calorimetry, sensible heat and latent heat,  the amount of heat required is 37.88 kJ.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

<h3>Sensible heat</h3>

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

<h3>Latent heat</h3>

Latent heat is defined as the energy required by a quantity of substance to change state.

When this change consists of changing from a solid to a liquid phase, it is called heat of fusion and when the change occurs from a liquid to a gaseous state, it is called heat of vaporization.

  • <u><em>25.60 °C to 0 °C</em></u>

First of all, you should know that the freezing point of water is 0°C. That is, at 0°C, water freezes and turns into ice.

So, you must lower the temperature from 25.60°C (in liquid state) to 0°C, in order to supply heat without changing state (sensible heat).

The amount of heat a body receives or transmits is determined by:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • c= Heat Capacity of Liquid= 4.184 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= 0 °C - 25.60 °C= - 25.6 °C

Replacing:

Q1= 4.184 \frac{J}{gC}× 185.5 g× (- 25.6 °C)

Solving:

<u><em>Q1= -19,868.98 J</em></u>

  • <u><em>Change of state</em></u>

The heat Q that is necessary to provide for a mass m of a certain substance to change phase is equal to

Q = m×L

where L is called the latent heat of the substance and depends on the type of phase change.

In this case, you know:

n= 185.5 grams× \frac{1mol}{18 grams}= 10.30 moles, where 18 \frac{g}{mol} is the molar mass of water, that is, the amount of mass that a substance contains in one mole.

ΔHfus= 6.01 \frac{kJ}{mol}

Replacing:

Q2= 10.30 moles×6.01 \frac{kJ}{mol}

Solving:

<u><em>Q2=61.903 kJ= 61,903 J</em></u>

  • <u><em>0 °C to -10.70 °C</em></u>

Similar to sensible heat previously calculated, you know:

  • c = Heat Capacity of Solid = 2.092 \frac{J}{gC}
  • m= 185.5 g
  • ΔT= Tfinal - Tinitial= -10.70 °C - 0 °C= -10.70 °C

Replacing:

Q3= 2.092 \frac{J}{gC} × 185.5 g× (-10.70) °C

Solving:

<u><em>Q3= -4,152.3062 J</em></u>

<h3>Total heat required</h3>

The total heat required is calculated as:  

Total heat required= Q1 + Q2 +Q3

Total heat required=-19,868.98 J + 61,903 J -4,152.3062 J

<u><em>Total heat required= 37,881.7138 J= 37.8817138 kJ= 37.88 kJ</em></u>

In summary, the amount of heat required is 37.88 kJ.

Learn more about calorimetry:

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7 0
2 years ago
The temperature at which a substance in its solid state melts into the same substance in a liquid is known as
larisa86 [58]

Answer:

0 C

Explanation:

8 0
4 years ago
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