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monitta
3 years ago
11

The following diagram represents a vertical cross section of sedimentary rock layers that have not been overturned. Which princi

ple best supports the conclusion that these layers have undergone extensive movement since deposition?
Chemistry
1 answer:
coldgirl [10]3 years ago
3 0
Deposited in horizontal layers.
You might be interested in
How would you prepare 175 mL of a 0.350kmol/m^3 calcium nitrate solution
SVEN [57.7K]
0,35 kmol/m³ = 0,35 mol/dm³ = 0,35 mol/L
175 mL = 0,175 L
*-*-*-*-*-*-*-*-*-*-*-*
C = n/V
n = 0,35×0,175
n = 0,06125 mol

mCa(NO₃)₂: 40+(14×2)+(16×6) = 164 g/mol

1 mol --------- 164g
0,06125 ---- X
X = 10,045g

To prepare 175 mL of 0,35M solution, add 10,045g of calcium nitrate and add water to a volume of 175ml.
3 0
3 years ago
How many moles of calcium chloride would react with 5. 99 moles of aluminum oxide?
slega [8]

There are 17.97 moles of calcium chloride would react with 5. 99 moles of aluminum oxide .

The balanced chemical equation between  reaction between calcium chloride and aluminum oxide is given as,

3CaCl_{2} (aq)+Al_{2} O_{3} (s) → 3CaO_{2} (s)+2Al Cl_{3} (aq)

The molar ratio of above reaction is  3:1

It means 3 moles of calcium chloride is require to react one mole of aluminum oxide.

The number of moles of calcium chloride requires to react with  5. 99 moles of  aluminum oxide  = 3 × 5. 99 = 17.97 moles

The equation in which number of atoms of elements in reactant side is equal to the number of atoms of elements in product side is called balanced chemical equation .

learn more about calcium chloride

brainly.com/question/15296925

#SPJ4

6 0
1 year ago
PLS HELP
alexandr1967 [171]

Answer:

Explanation:

A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1

5 0
3 years ago
Read 2 more answers
HELPP! pls
pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒  \frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}

or,

⇒  Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr

⇒                      =\frac{1}{2}\times 4.96

⇒                      =2.48 \ mole

(b)

The limiting reactant is:

= HBr

(c)

The excess reactant is:

= Al

6 0
2 years ago
If air is contaminated with unwanted substances, it is said to be polluted. Which of these places would most likely to have poll
lianna [129]

Answer:

Forest. Because as u saw last year with the Australian forest fire it was bad.

5 0
2 years ago
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