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2 years ago

In a class of 20 students,12 were girls and the rest were boys

Mathematics

2 answers:

Ira Lisetskai [31]2 years ago

7 0

It’s definitely A (:

VARVARA [1.3K]2 years ago

4 0

A) 8/20 —>simplified as 2/5
b) 12/20 —> simplified as 3/5
c) 60% girls
4) 0.4 boys

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Which of the following functions have a vertical asymptote for values of θ such that cos θ = 1? Select two answers.

valentina_108 [34]

Well costheta=1, at 0, 2pi,...
knowing this we can exclude the first two as the are not undefined anywhere.
tan is sin/cos, at 0 sin is also 0 so it becomes 0/1 which is 0, not undefined.
sec is1/cos, cos is 1, this is just 1
csc is 1/sin, sin is 0, 1/0 is undefined, meaning there will be an asymptote
cot is cos/sin, this is again 1/0, so it is also an asymptote
The last two answers are the ones you want

3 0

3 years ago

Can someone please help me on this ASAP

OLEGan [10]

<span>(a) Triangles ABC and PQR are similar triangles since they both share 2 congruent angles and therefore their 3rd angle is also congruent. So the triangles are similar due to the AAA similarity theorem. (b) The area of triangle PQR is 1 million times larger than the area of triangle ABC. This can be shown since the area of a triangle is 1/2 base times height. You can show that the base of triangle PQR is 1000 times larger than the base of triangle ABC. And since all the sides are in proportion to each other, the height of triangle PQR is also 1000 times larger than the height of triangle ABC. And since 1000 times 1000 equals 1,000,000 or 1 million, the area of triangle PQR is 1 million times larger than triangle ABC.</span>

8 0

2 years ago

Read 2 more answers

One number twice another number sum of 36

san4es73 [151]

The number is 23 thats what i got

7 0

2 years ago

Can someone PLEASE help me with Trigonometry???

Svetach [21]

$\bf sin^2(2\theta)-7sin(2\theta)-1=0\\\\
-------------------------------\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{49-4(1)(-1)}}{2(1)}\implies sin(2\theta)=\cfrac{7\pm\sqrt{49+4}}{2}
\\\\\\
sin(2\theta)=\cfrac{7\pm\sqrt{53}}{2}\implies 2\theta=sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)
\\\\\\
\theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}$

but anyway, the numerator will give the angles, and θ is just half of each

$\bf \theta=\cfrac{sin^{-1}\left( \frac{7\pm\sqrt{53}}{2} \right)}{2}\\\\
-------------------------------\\\\
sin^{-1}\left( \frac{7+\sqrt{53}}{2} \right)\implies sin^{-1}(7.14)\impliedby \textit{greater than 1, no good}
\\\\\\
sin^{-1}\left( \frac{7-\sqrt{53}}{2} \right)\implies sin^{-1}(-0.14) \approx -8.05^o
\\\\\\
\theta=\cfrac{-8.05}{2}\implies \theta=-4.025$

ok... that's a negative tiny angle, is in the 4th quadrant, if we stick to the range given, from 0 to 360, so we have to use the positive version of it, 360-4.025

so the angle is 355.975°

now, the 3rd quadrant has another angle whose sine is negative, so... if we move from the 180° line down by 4.025, we end up at 184.025°

and those are the only two angles, because, on the 2nd and 1st quadrants, the sine is positive, so it wouldn't have an angle there

7 0

3 years ago

The total area of a picture and its frame can be represented by ^l + 2f h^w + 2f h, where l and w represent the length and width

jok3333 [9.3K]

The answers to the question are

b. (l + 2f) (w + 2f)

c. f + 4, f + 6

d. 52.25

a. The diagram is an attachment.

<h3>B. How to solve for the binomial multiplication</h3>

The equation says

(l + 2f) (w + 2f)

We have the lengths of w and l as 8 and 12 respectively. Hence we have

(8 + 2f) (12 + 2f) as the area

c. (8 + 2f) (12 + 2f)

= 96 + 16f + 24f + 4f²

= 4f² + 40 f + 96

We have to factorize this using the quadratic equation calculator

f + 4, f + 6

= f = -4 and f = -6

d. If it is 1.25 thick we would have

1.25 x 2 = 2.5

12 - 2.5 = 9.5

8 - 2.5 = 5.5

Area = l * w

= 5.5 * 9.5

= 52.25

Read mire on binomial multiplication here:

brainly.com/question/20353197

#SPJ1

6 0

1 year ago