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AURORKA [14]
3 years ago
7

30 points for anyone that can help please?

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0

Answer:

A) 1.5

B) x^2-23x+42 = (x-2)(x-21)

C) x=2, x=21

Step-by-step explanation:

a) 15 -2x / 3 = 4

15-2x = 12  (Times by three on both sides)

-2x = -3

x = -3/-2 = 3/2 = 1.5

b) x^2-23x+42

x^2-23x+42 = (x-2)(x-21)

c) x^2 -23x +42 = 0

x=2, x=21

(x-2) = 0  ⇒  x = 2

(x-21) = 0  ⇒  x = 21

Wittaler [7]3 years ago
5 0

Answer:

a) x = 1.5

b) (x-21)(x-2)

c) x = 2, 21

Step-by-step explanation:

a) Solve for x

(15 -2x)/3 = 4

15-2x = 12

2x = 3

x = 1.5

b) Factorize

x²-23x +42

x²-21x-2x+42

x(x-21)-2(x-21)

(x-21)(x-2)

c) Solve the two possible answers below

x^2 -23x +42 = 0

(x-21)(x-2) = 0

x = 2, 21

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Answer:

The coordinates of the point is (5.5, -2)

Step-by-step explanation:

Okay, what we want to do here is to get the point that divides the line that joins the points (3,3) to (7,-5) in the ratio 5 to 3

Generally, given the ratio a:b and we want to divide the line joining the points (x1,y1) and (x2,y2) in that ratio, we use the condensed formula below;

Let’s call the point dividing the line in the given ratio z.

The coordinates of Z is;

{(bx1 + ax2)/(a+b), (by1 + ay2)/(a+b)}

In this question (x1,y1) = (3,3)

While (x2,y2) = (7,-5)

while a:b = 5:3

Substituting these values into the coordinate equation for point z, we have ;

{((3(3) + 5(7))/(5+3), ((3)(3) + 5(-5))/(5+3)}

= {44/8 , -16/8} = {5.5, -2}

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Have a pic of the problem?
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Andy runs 434.56 meters in 62.08 seconds. If Andy runs at a constant speed, how far does he run in one second?
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lbvjy [14]

In the question, we are given with speed of a car and the distance it have to travel.

Given:

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So, we can say that in 1 hour, the car can travel 40 km. And we have to find the time taken by the car to travel 60 km.

This can be easily done by using the Speed, Distance and Time formula which says:

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So, let's solve by using this formula.

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\large{ \boxed{ \bf{ \purple{t = 1  \dfrac{1}{2} hr}}}}

And we are done !!

#CarryOnLearning....

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