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AURORKA [14]
3 years ago
7

30 points for anyone that can help please?

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0

Answer:

A) 1.5

B) x^2-23x+42 = (x-2)(x-21)

C) x=2, x=21

Step-by-step explanation:

a) 15 -2x / 3 = 4

15-2x = 12  (Times by three on both sides)

-2x = -3

x = -3/-2 = 3/2 = 1.5

b) x^2-23x+42

x^2-23x+42 = (x-2)(x-21)

c) x^2 -23x +42 = 0

x=2, x=21

(x-2) = 0  ⇒  x = 2

(x-21) = 0  ⇒  x = 21

Wittaler [7]3 years ago
5 0

Answer:

a) x = 1.5

b) (x-21)(x-2)

c) x = 2, 21

Step-by-step explanation:

a) Solve for x

(15 -2x)/3 = 4

15-2x = 12

2x = 3

x = 1.5

b) Factorize

x²-23x +42

x²-21x-2x+42

x(x-21)-2(x-21)

(x-21)(x-2)

c) Solve the two possible answers below

x^2 -23x +42 = 0

(x-21)(x-2) = 0

x = 2, 21

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(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

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