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o-na [289]
3 years ago
8

Can you help plz 7 + 56 y

Mathematics
2 answers:
ivolga24 [154]3 years ago
8 0

I think it's 56y + 7, is what I'm pretty sure of.

valkas [14]3 years ago
8 0

Answer:

Simplifying

7 = 56y

Solving

7 = 56y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-56y' to each side of the equation.

7 + -56y = 56y + -56y

Combine like terms: 56y + -56y = 0

7 + -56y = 0

Add '-7' to each side of the equation.

7 + -7 + -56y = 0 + -7

Combine like terms: 7 + -7 = 0

0 + -56y = 0 + -7

-56y = 0 + -7

Combine like terms: 0 + -7 = -7

-56y = -7

Divide each side by '-56'.

y = 0.125

Simplifying

y = 0.125

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How do you do this?<br> Please help x
kirill115 [55]

Answer:

Step-by-step explanation:

a). Given equation is y = 3x - 4

   Table for the input-output values is,

   x          -1           0          1            2          3

   y          -7          -4         -1           2          5

Now we can plot these points on the graph (graph attached).

b). Equation is y = -2x + 3

   Table for the input-output values will be,

  x       -1          0         1        2       3

  y       5          3         1        -1       -3

3 0
2 years ago
which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1​
lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. y=\sec x

B. y= \tan x

C. y= \cot x

D. y= \csc x

Answer:

A. y=\sec x

D. y=\csc x

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: y=\sec x

We know that, the \sec x=\frac{1}{\cos x}

The range of \cos x is from -1 to 1 given as [-1, 1]. So,

|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1

Therefore, on removing the absolute sign, we rewrite the secant function as:

\sec x\leq -1\ or\ \sec x\geq 1\\

Therefore, the range of y=\sec x is all real numbers greater than or equal to 1 or less than or equal to-1​.

Choice B: y= \tan x

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: y= \cot x

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: y=\csc x

We know that, the \csc x=\frac{1}{\sin x}

The range of \sin x is from -1 to 1 given as [-1, 1]. So,

|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

\csc x\leq -1\ or\ \csc x\geq 1\\

Therefore, the range of y=\csc x is all real numbers greater than or equal to 1 or less than or equal to-1​.

6 0
3 years ago
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motikmotik
The answer is 2/3 shirt per hour.
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Read 2 more answers
What is the value of a 3 - b 2 for a = 3 and b = ?
stellarik [79]

Answer:

a^3 - b^2 for a = 3 and b = 1/2

3^3 - (1/2)^2

= 27 - 1/4

= 26 3/4

Step-by-step explanation:

7 0
3 years ago
Solutions for x2 −22x+121=49
slamgirl [31]
The answer is d I think
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2 years ago
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