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Anna71 [15]
3 years ago
6

A rock is projected directly upward from ground level with an initial velocity of 90 feet per second. Give the function that des

cribes the height of the rock in terms of time t.
Mathematics
2 answers:
JulijaS [17]3 years ago
6 0

Answer:

Step-by-step explanation:

From the fourth law of motion

h = ut + 0.5gt^2

h =90t +0.5(10)t^2

Converting 90 frets/s into m/s

h =27.43t +5t^2

timurjin [86]3 years ago
5 0

Answer:

Step-by-step explanation:

The initial velocity, u of the obect when it was projected vertically is 90 feet per second

The acceleration of the object is 32.17405 ft/s2 which is approximately 32.2ft/s2. This is same as acceleration due to gravity.

Since the object is moving upwards, it is moving in opposite direction to the gravitational force. Therefore,

acceleration of the object, g is negative.

g = - 32.2ft/s2

u = 90 feet per second

H = the height of the object in feets

t = time in seconds

Applying newtons law of motion

H = ut + gt^2/2

H = 90t + (-32.2×t^2)/2

H = 90t - 16.1t^2

H = - 16.1t^2 + 90t^2

The function is

f(t) = - 16.1t^2 + 90t^2

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you are a billing clerk. five hours are charged to an account at $70 per hour. how much should you bill the account
Sindrei [870]

Answer:

The answer is $350.00

Step-by-step explanation:

The answer would be $350.00 because if you are charging an account forfive hours of whatever, and it costs $70.00 and hour, then you would multiply the two numbers. 5*$70 which equals $350.

3 0
3 years ago
Convert the equation r = 12 sin theta to Cartesian coordinates. Describe the resulting curve.
VLD [36.1K]

Answer:

Step-by-step explanation:

Given that there is a polar equation as

r=12 sin \theta

This has to be converted into cartesian.

We know the conversion is

r^2 =x^2+y^2 \\tan \theta = \frac{y}{x}

Using this we can say that

sin^2 \theta = 1-cos^2 \theta \\= 1-\frac{1}{sec^2 \theta} \\=1-\frac{1}{1+tan^2 \theta} \\=1-\frac{1}{1+\frac{y^2}{x^2} } \\=1-\frac{x^2}{x^2+y^2} \\=\frac{y^2}{y^2+y^2}

\sqrt{x^2+y^2} =12(\frac{y}{\sqrt{x^2+y^2} } \\x^2+y^2 =12y\\x^2+y^2-12y+36 = 36\\x^2+(y-6)^2 = 6^2}

Circle with centre (0,6) and radius 6.

7 0
3 years ago
HELPP PLEASEEE
MrRa [10]

Answer: The answer to your question is 6\sqrt{3}

Step-by-step explanation:

To solve this problem we will use proportions. We will compare the largest right triangle and the medium size triangle.

                          Medium triangle                     Large triangle

hypotenuse                 y                                            9 + 3

adjacent size               9                                               y

- Write the proportions

                                  y/9 = (9 + 3)/y

-Solve for y

                                  y² = 9(12)

                                  y² = 108

                                  y =   \sqrt{180}

-Find the prime factors of 108

                                  108  2

54 2

                                     27 3

                                      9  3

                                      3   3

                                       1

then,       108 = 2² 3³

-Expressthe root as fractional exponents

                                  2²/² 3²/² 3¹/²

-Simplification

                                   2(3)(3)¹/²

-Result

                                      6\sqrt{3}

8 0
3 years ago
Solve for x: 2/3=8/x+6
Tresset [83]

Answer:

x = 6

Step-by-step explanation:

2/3=8/x+6

Using cross products

2 * (x+6) = 3*8

2(x+6) = 24

Divide by 2

x+6 =12

Subtract 6

x = 6

8 0
3 years ago
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Sladkaya [172]
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