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Vesna [10]
3 years ago
15

8 less than 2 times a number is greater than the sum of the same number and 9

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

step-by-step explanation:

every time we see "a number" or "the same number," we can add a variable (we'll use x here).  rewriting the problem, we get: 8 less than 2 times x is gr8er than the sum of  x and 9.  

next, we can work backwards to write an inequality.  we know from the word problem above that the number on the left side of the equation is 8 less than 2x, so we can rewrite that part like this: 2x-8.

for the right side of the equation, all we have to do is simplify "the sum of x and 9" to x + 9.  so now the inequality should look like this: 2x - 8 > x + 9.  

now we'll solve the inequality just like an equation: subtract x from both sides of the inequality, so now we have: x - 8 > 9.

then, we can add 8 to both sides to get the x by itself, and we get the answer: x > 15

hope this helps! <em>:)</em>

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A new car is purchased for \$18,000$18,000 and over time its value depreciates by one half every 3.5 years. How long, to the nea
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15.1

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3 years ago
To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks. How many meters did Sonya swim in tho
Strike441 [17]

Answer:

Distance swam by Sonya in 3 weeks = 19740 m

Step-by-step explanation:

To practice for a competition, Sonya swam 0.94 kilometer in the pool each day for 3 weeks.

Number of days in 1 week = 7

Number of weeks she swam = 3

Total number of days she swam = 3 x 7 = 21 days

Distance swam per day = 0.94 km

Total distance swam = Total number of days she swam x Distance swam per day

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1/2 (6x-10) - x =<br><br> What's the other side of the equation?
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Step-by-step explanation:

1/2 (6x-10) - x

Opening bracket

= 6x/2 - 10/2 - x

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4 0
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3)Find the GCF and LCM of 10 and 28. Show your work.<br><br> HELP LAST QUESTION!!!!!
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Step-by-step explanation:

8 0
3 years ago
Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =
swat32

Answer:

Test statistic, t_{s} = -0.603 (to 3 dp)

Step-by-step explanation:

Deviation, d = x -y

Sample mean for the deviation

\bar{d} = \frac{\sum x-y}{n}

\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625

Standard deviation: SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1}  }

\sum d^{2}  = (28-26)^2 + (31-27)^2 +(20-26)^2 +(25-25)^2 +(28-29)^2 +(27-32)^2 +(33-33)^2 +(35-34)^2\\\sum d^{2}  = 63

SD = \sqrt{\frac{63 - 8 *  (-0.625)^2}{8-1}  }

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

t_{s} = \frac{ \bar{d}}{s_{d}/\sqrt{n}  } \\t_{s} = \frac{- 0.625}{2.93/\sqrt{8}  }

t_{s} = -0.6033

6 0
3 years ago
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