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Vesna [10]
3 years ago
15

8 less than 2 times a number is greater than the sum of the same number and 9

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

step-by-step explanation:

every time we see "a number" or "the same number," we can add a variable (we'll use x here).  rewriting the problem, we get: 8 less than 2 times x is gr8er than the sum of  x and 9.  

next, we can work backwards to write an inequality.  we know from the word problem above that the number on the left side of the equation is 8 less than 2x, so we can rewrite that part like this: 2x-8.

for the right side of the equation, all we have to do is simplify "the sum of x and 9" to x + 9.  so now the inequality should look like this: 2x - 8 > x + 9.  

now we'll solve the inequality just like an equation: subtract x from both sides of the inequality, so now we have: x - 8 > 9.

then, we can add 8 to both sides to get the x by itself, and we get the answer: x > 15

hope this helps! <em>:)</em>

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How would I solve <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20x-%5Cfrac%7B5%7D%7B3%7D%20%3D-%5Cfrac%7B1%7D%7B2%7D%
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