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mote1985 [20]
4 years ago
11

Electron A falls from energy level X to energy level Y and releases blue light. Electron B falls from energy level Y to energy l

evel Z and releases red light. Which transition, from X to Y or from Y to Z, has a greater energy difference? Explain your answer and how you arrived at it. Use a diagram of the electromagnetic spectrum.

Chemistry
1 answer:
MrMuchimi4 years ago
5 0

Answer: Transition from X to Y will have greater energy difference.

Explanation: For studying the energy difference, we require Planck's equation.

                                E=\frac{hc}{\lambda}

where, h = Planck's Constant

c = Speed of light

E = Energy

\lambda = Wavelength of particle

From the equation, it is visible that the energy and wavelength follow inverse relation which means that with low wavelength value, energy will be the highest and vice-versa.

As electron A falls from X-energy level to Y-energy level, it releases blue light which has low wavelength value (around 470 nm) which means that it has high energy.

Similarly, Electron B releases red light when it falls from Y-energy level to Z-energy level, which has high wavelength value (around 700 nm), giving it a low energy value.

Energy Difference between X-energy level and Y-energy level will be more.


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When the solid and liquid phases are present together simultaneously which phase solid liquid contains the greater amount of ene
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4 years ago
Hydroxylapatite, Ca10(PO4)6(OH)2, has a solubility constant of Ksp = 2.34 x 10^-59. Solid hydroxylapatite is dissolved in water
nadezda [96]

Answer:

The concentration of [Ca²⁺] is 8.47 x 10⁻³ M

Explanation:

We consider the solubility of hydroxyapatite,

Ca₁₀(PO₄)₆(OH)₂ ⇔ 10Ca²⁺ + 6PO₄³⁻ + 2 OH⁻

Assumed that there is <em>a</em> mol of hydoxyapatite disolved in water, yielding <em>10a</em> mol Ca²⁺ of  and <em>6a</em> mol of PO₄³⁻

We also have Ksp equation,

Ksp = [Ca²⁺]¹⁰ x [PO₄³⁻]⁶ x [OH⁻]² = 2.34 x 10⁻⁵⁹

     ⇔  10a¹⁰ x 6a⁶ x (5.30 x 10⁻⁶)² = 2.24 x 10⁻⁵⁹

     ⇔  60a¹⁶                                    = 2.24 x 10⁻⁵⁹ / 5.30 x 10⁻¹²

     ⇔  a¹⁶                                         = 0.007 x 10⁻⁴⁷ = 7 x 10⁻⁵⁰

     ⇔  a                                           = \sqrt[16]{7 . 10^{-50} } =  8.47 x 10⁻⁴

Hence,

[Ca²⁺] = 10<em>a</em> = 8.47 x 10⁻³ M

3 0
4 years ago
Which best describes Earth's magnetic field lines?
STatiana [176]

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The field lines go out of Earth near Antarctica, enter Earth in northern Canada, and are not aligned with the geographic poles.

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The two poles North pole and South pole of the earth are distinct from the magnetic north pole and south pole of the earth. The magnetic north pole is the point from where the magnetic field of the Earth points downwards in the vertical direction. There is a gradual change in the magnetic poles with the passing of the time. The magnetic fields have an extension from the interior of the Earth to the outer space.

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3 years ago
When you placed the chromatography paper in the Petri dish containing the salt-water solution solvent, what would have happened
BaLLatris [955]

Answer:

It will not achieve the desired separation

Explanation:

Chromatography is a separation method that involves the use of a stationary phase and a mobile phase. The stationary phase is immobile, in the particular instance of this question, the stationary phase is paper. The mobile phase is the appropriate solvent, in this case, a salt-water solution.

If the level of solvent is above the dye spots, it will introduce error into the separation. The solvent (if volatile) may evaporate without drawing up and separating the solute. Secondly, the solvent may simply dissolve the spots without achieving any meaningful separation of the components in the system. This second reason is particularly why the salt solution must be below the dye spots in this chromatographic separation.

8 0
3 years ago
For the reaction H2(g) + 12(g) = 2HI(g), Kc = 50.2 at 445°C. If
Studentka2010 [4]

Qc < Kc, the reaction proceeds from left to right to reach equilibrium

<h3>Further explanation </h3>

Given

K = 50.2 at 445°C

[H2] = [I2] = [HI] = 1.75 × 10⁻³ M At 445ºC

Reaction

H2(g) + I2(g) ⇔2HI(g)

Required

Qc

Solution

Qc for the reaction

\tt Qc=\dfrac{[HI]^2}{[I_2][H_2]}\\\\Qc=\dfrac{(1.75.10^{-3})^2}{1.75.10^{-3}\times 1.75\.10^{-3}}=1  

Qc < Kc ⇒ reaction from left(reactants) to right (products) (the reaction will shift on the right) until it reaches equilibrium (Qc = Kc)  

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