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lidiya [134]
4 years ago
13

PLEASE HELP ME AGAIN!!!

Chemistry
1 answer:
rosijanka [135]4 years ago
6 0
I would believe it to be the second
CH3CL.
(A quick way to find them is werhere or not they are symmetrical but there are a lot of exceptions)
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odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add
Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

Explanation :

First we have to calculate the moles of H_2SO_4.

\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}

Given:

Molar mass of H_2SO_4 = 98 g/mole

Mass of H_2SO_4 = 6.05\times 10^3kg=6.05\times 10^6g

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol

The moles of H_2SO_4 is, 6.17\times 10^4mol

Now we have to calculate the moles of Na_2CO_3

The balanced neutralization reaction is:

Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3

From the balanced chemical reaction we conclude that,

As, 1 mole of H_2SO_4 neutralizes 1 mole of Na_2CO_3

So, 6.17\times 10^4mol of H_2SO_4 neutralizes

Now we have to calculate the mass of Na_2CO_3

\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3

Molar mass of Na_2CO_3 = 106 g/mole

\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg

Thus, the mass of sodium carbonate added to neutralize must be, 6.54\times 10^3kg

3 0
4 years ago
The solution remaining from Part A, which contains 0.0100 M Ni2 and Fe2 ions, is still saturated with H2S gas, producing a conce
Arturiano [62]

Answer:I think the answer would be B

Explanation:

5 0
3 years ago
water droplets tend to have a spherical, round shape, Explain ths fact in terms of the polar nature of water molecules
Doss [256]
What does it happen in smallest scale? 
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<span>"TWO-PHASE INTERFACIAL FORCEs". </span>
<span>At boundary surface between two aggregation phases, you may attribute upper energy level to molecules standing at the boundary zone. So, it has to define INTERFACIAL FORCEs WHICH ACT TO REMODEL SHAPE AND EXTENSION OF MEETING PHASEs. </span>
<span>In your case, Water's Droplet is a liquid phase surrounded by Air (e.g. gas phase) and Interfacial Forces act to dominate Boundary-Surface. </span>
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6 0
3 years ago
8. When rubidium and fluorine combine to produce the compound RbF, che ions
skelet666 [1.2K]

Answer:

The answer is C, both krypton and neon.

Explanation:

I got the answer wrong and my teacher told me that c is the right answer choice

8 0
3 years ago
The effective nuclear charge for an atom is less than the actual nuclear charge due to
Irina18 [472]

Answer:

A = shielding.

Explanation:

The addition of electron causes the atomic size increase from top to bottom due to increase in atomic number.

As the atomic number increased one more electron is added and because of this electron on more electronic shell is added. Thus the electron become more away from the nucleus as many of other electrons are present in the way from nucleus to the outer electrons.

The hold of nucleus becomes weaker. Although nuclear charge is also increased but at the same time other electrons shield the respective electrons. So effective nuclear charge is weaker than the actual nuclear charge.

Because of this shielding it is easy to remove the electrons or we can say ionization energy decreases.

3 0
4 years ago
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