1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sveticcg [70]
3 years ago
7

What is the percent of the blue gumballs

Mathematics
1 answer:
kramer3 years ago
8 0
63/170= 37% 
You can divide 63/170 and you get 0.37 as decimal form but when trying to find the percent you always multiply by 100 to get a decimal to a percent and then u found your answer

You might be interested in
Y=-1/2x+11 that passes through (4,-8)
kompoz [17]

A line in point-slope form has the equation


y = mx + b


where m=slope (increase in y for unit increase in x), and

b=y-intercept (value of y where line cuts y-axis)


The original line is

y=(-1/2)x + 11

so

slope = m = -1/2


Any line perpendicular to a line with slope m has a slope of m1=-1/m

So the slope m1 of the required line

m1 = -1 / (-1/2) = +2


and the required line therefore has an equation of

y=2x+b


Knowing that the line passes through P1=(x1, y1)=(4,-8), we can find b using the point slope form of a line with slope m : (y-y1) = m(x-x1)

where m=+2 as found above.


Substituting values, m=+2, x1=4, y1= -8

y-(-8) = +2(x--4)

simplify

y+8 = 2x-8

=>

y=2x-16 (in point slope form)

8 0
3 years ago
Solve for y a(n+y)=10y+32 what is the answer
Solnce55 [7]
A (n + y) = 10y + 32
(an + ay) = 10y + 32

an + ay = 32 + 10y

Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y) 
- 32 + an + ay + (-10y) = 10y + (-10y)

</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0

Thi could not be determined. (no solution)</span>
6 0
3 years ago
Is this enough to see​
Oksana_A [137]
No we can’t see the question




Jfjfjdjfjfjfhfhfhfhdhdbdhdbdhdhdh
4 0
3 years ago
Read 2 more answers
Money is borrowed at 15% simple interest. After one year,$1181.05 pays off the loan. How much was originally borrowed?
marin [14]

Answer: $787 was originally borrowed.

Step-by-step explanation:

The formula for determining simple interest is expressed as

I = PRT/100

Where

I represents interest paid on the loan.

P represents the principal or amount taken as loan

R represents interest rate

T represents the duration of the loan in years.

From the information given,

Total amount = $1181.05

Interest = total amount - principal

I = 1181.05 - P

R = 15%

T = 1 year

Therefore,

1181.05 - P

Therefore,

1181.05 - P = (P × 15 × 1)/100

1181.05 - P = 0.15P

P + 0.15P = 1181.0

1.5P = 1181.05

P = 1181.05/1.5

P = $787

5 0
3 years ago
How do u convert a fraction into a decimal
lesya692 [45]
You have to divide the numerator (top number) by the denominator (bottom number). For example, 1/2 is 0.5
However, some end up as never-ending decimals, like 1/3, which converts to 0.333 repeating.
3 0
3 years ago
Other questions:
  • How do i write 2 perfect squares that each have a value greater then 100 and less that 200
    8·1 answer
  • What is the area of circle? Show work !!!
    13·1 answer
  • The Eat Right Fruit Company sells 9/15 of a ton of bananas to one customer and 13/15 of a ton of bananas to another customer. Ho
    5·1 answer
  • Mardi received an inheritance of $40,000. She invested part at 9% and the rest at 12%. Her total annual income from the investme
    14·1 answer
  • Someone please help me with this
    13·1 answer
  • SIMPLE Factoring by Grouping
    10·1 answer
  • Is 9x^2 - 12x + 4 a perfect square? Why?
    6·2 answers
  • Graph the line that passes through the points (1,-9) and (1,-3) and determine the equation of the line
    12·1 answer
  • 25 minutes before 9 at night is written as _:__p.m.​
    14·1 answer
  • A 45 gram sample of a substance that’s used to preserve fruit and vegetables has a K-value of 0.1085
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!