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Viefleur [7K]
3 years ago
7

What is the solution to this system of equations? 4x + 5y = 7 3x – 2y = –12

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
5 0

The answer is (-2,3)

hope you have a great day ;)

jolli1 [7]3 years ago
4 0

Answer:   (x, y) = (-2, 3) is the required solution.

Step-by-step explanation:  We are given to find the solution to the following system of linear equations:

4x+5y=7~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\3x-2y=-12~~~~~~~~~~~~~~~~~~~(ii)

Multiplying equation (i) by 3 and equation (ii) by 4, we have

12x+15y=21~~~~~~~~~~~~~~~~~(iii)\\\\12x-8y=-48~~~~~~~~~~~~~~~~(iv)

Subtracting equation (iv) from equation (iii), we get

(12x+15y)-(12x-8y)=21-(-48)\\\\\Rightarrow 12x+15y-12x+8y=21+48\\\\\Rightarrow 23y=69\\\\\Rightarrow y=3,

and from equation (i), we get

4x+5\times 3=7\\\\\Rightarrow 4x+15=7\\\\\Rightarrow 4x=-8\\\\\Rightarrow x=-2.

Therefore, the solution to the given system is  x = - 2, y = 3.

Thus, (x, y) = (-2, 3) is the required solution.

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3/2 x 63 is greater
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BabaBlast [244]

Answer:

3x-12=y

which equals to

1/y=1/(3x-12)

Now,multiply both sides by x

x/y=x/(3x-12)

8x/2y=4x/y=4x/(3x-12)

Step-by-step explanation:

''.''

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3 years ago
Which value is not in the range of the function? А. 0<br> B. 3 <br>C. 4 <br>D. 5​
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B

Step-by-step explanation:

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2 years ago
Tanya ran 400 meters on Tuesday and 800 on Wednesday. If she ran 16,256 meters in all, how many did she run on Thursday? Show wo
loris [4]
Here's what I got. Hope that helps!

5 0
4 years ago
Read 2 more answers
If T: (x, y) → (x + 6, y + 4), then T-1: (x,y) → _____.
alexgriva [62]

T is a linear transformation from R²→R² with basis {(1,0),(0,1)}
T: (x,y)→(x+6,y+4)

A function from one vector space to another that preserves the underlying (linear) structure of each vector space is called a linear transformation.

Then the vector (1,0) goes to (1+6,4)=(7,4)=7(1,0)+4(0,1)

and the vector (0,1) goes to (6,1+4)=(6,5)=6(1,0)+5(0,1)

So, the matrix of the transformation is

\left[\begin{array}{ccc}7&6\\4&5\end{array}\right]

The inverse of the matrix is

\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]

So, the Inverse Transformation is given by

T^{-1}(x,y)=\left[\begin{array}{ccc}\frac{5}{11}&\frac{-6}{11}\\ \\\frac{-4}{11}&\frac{7}{11}\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right] =(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

So, no option is correct. And the answer is

T^{-1}(x,y)=(\frac{5x-6y}{11}, \frac{-4x+7y}{11})

Learn more about linear transformations here-

brainly.com/question/13005179

#SPJ10

5 0
2 years ago
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