Using V = ⅓[base area×height]
V= ⅓[ (5.5÷4)² × 2.6]
v= ⅓[ 4.92]
v = 1.6m³
Let us use the following conversions:
1 cm = 10 mm
1 meter = 100 cm = 1000 mm
Given:
p = 800 mm
q = 200 cm = 2000 mm
r= 4 m = 4000
X = sum of the distance around each circle
X = p+q+r
X = 800+2000+4000
<span>X = 6800 mm or 680 cm or 6.80 m</span>
Answer:
Yes, it is a quadratic equation.
Step-by-step explanation:
<em>Let's solve it to make it a quadratic equation:</em>
=> 
=> x²+1 = 5x²
=> 5x²-x²-1 = 0
=> 4x²-1 = 0
<em>Comparing it with the standard form of quadratic equation i.e. </em>
So, we get
a = 4 , b = 0 and c = -1
<u><em>So, yes. It is a quadratic equation and it is a pure quadratic equation since b is equal to 0.</em></u>
Answer:
Third option : 9^10 / 9^2
Step-by-step explanation:
9^2 . 9^6
Formula / Identity : -
a^m . a^n = a^( m + n )
Here,
a = 9
m = 2
n = 6
9^2 . 9^6
= 9^( 2 + 6 )
=9^8
9^10 / 9^2
Formula / Identity : -
a^m / a^n = a^( m - n )
Here,
a = 9
m = 10
n = 2
9^10 / 9^2
= 9^( 10 - 2 )
= 9^8
Therefore,
9^10 / 9^2 is equivalent to 9^2 . 9^6.
