The slope of AC is -0.4
Proof:
In triangles ABC and DBE,
∠DBE is common to both triangles.
AB = 2DB (D is the midpoint of the interval AB)
Also, BC = 2BE (E is the midpoint of the interval BC)
Thus triangles ABC and DBE are similar in the ratio 2:1
Since, they are similar, ∠BDE must equal ∠BAC (corresponding angles in similar triangles)
If ∠BDE = ∠BAC, DE must be parallel to AC (corresponding angles are equal along parallel lines)
Thus, the slope of AC = the slope of DE
Thus, the slope of AC is -0.4
-3(x - 4) + 15 = 3x - 14 + 2x
Multiply the -3 into (x - 4)
-3x + 12 + 15 = 3x - 14 + 2x
Combine like terms
-3x + 27 = 5x - 14
Add 3x on both sides
-3x + 27 + 3x = 5x - 14 + 3x
27 = 8x - 14
Add 14 on both sides
27 + 14 = 8x - 14 + 14
41 = 8x
Divide 8 on both sides
Hmm. I'm not the best at math, but I've found that:
The probability of ONE sixth grader being chosen out of each bag was:
1st Bag: 30%
2nd Bag: 40%
3rd Bag: 60%
4th Bag: 60%
5th Bag: 50%
So, I multiplied the probability by itself to find the probability of two things happening at the same time, the probability of TWO sixth graders being chosen:
1st Bag: 30% * 30% = 9%
2nd Bag: 40% * 40% = 16%
3rd Bag: 60% * 60% = 36%
4th Bag: 60% * 60% = 36%
5th Bag: 50% * 50% = 25%
<span>So, I found the Proability of TWO sixth graders being chosen at the same time, but now I have to find the experimental probability of it based on the information given.
</span>
I found this difficult to do, because I myself haven't learned it yet.
So I averaged out all 5 bags and found that:
<span>The Average experimental probability of TWO sixth graders being chosen randomly from the same bag with 4 Sixth Graders and 7 Seventh Graders in it, with experimental data
is:</span> <span>24.4%
</span>Here's an Example: https://math.stackexchange.com/questions/293668/whats-the-probability-if-getting-the-same-objects-of...
12y +6 is the answer to that question
Answer:
at least by 11am because she can get on the bus and sit wherever she wants to