We have that
<span>A' (2,1)
C(-2,2)-------> </span>Using the transformation-----> C' (-2+2,2+1)----> C' (0,3)
with
A' (2,1) and C' (0,3)
find the distance <span>C'A'
d=</span>√[(y2-y1)²+(x2-x1)²]----> d=√[(3-1)²+(0-2)²]----> d=√8----> 2√2 units
the answer is
the distance C'A' is 2√2 units
A combination is the weight of the two dogs added. If one dog weighs 15 kilos, while the other weighs 13 kilos, we must add 15 to 13. 15 plus 13 is 28, so the combination of the two dogs is 28.
Answer:
Domain: (-∞, ∞)
Range: (0,∞)
Step-by-step explanation:
Exponential functions are curves which approach a horizontal asymptote usually at y=0 or the x-axis unless a value has been added to it. If it has, the curve shifts. This function has addition on the exponent but not to the whole function so it does not change the asymptote. Its y - values remain between 0 and ∞. This is the range, the set of y values.
However, the range of exponentials can change based on the leading coefficient. If it is negative the graph flips upside down and its range goes to -∞. This doesn't have it either.
The addition to 1 on the exponent shifts the function to the left but doesn't change the range.
In exponential functions, the x values are usually not affected and all are included in the function. Even though it shifts, the domain doesn't change either. Its domain is (-∞, ∞).
Domain: (-∞, ∞)
Range: (0,∞)
