Answer:
B. 6.2
Step-by-step explanation:
The calculation is done by hand and verified by a TI-84 calculator.
Answer:
Since we know that ABCD ~ EFGH, we have the ratios:
EF/AB = GH/CD
=> 0.4/1.2 = x/1.8
=> x = (1.8 . 0.4)/1.2 = 0.6
So x = 0.6
There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
Step-by-step explanation:
itulog mo nalang yan, walang ganun lods
I’m confused what we are suppose to do
