It is basic. since it is a salt .
[Ne] 3s² 3p⁴
Not sure if that’s right
Answer:
The answer to your question is 59.5 g
Explanation:
Chemical reaction
4Al + 3O₂ ⇒ 2Al₂O₃
Data
mass of Al₂O₃ = ?
mass of Al = 31.5 g
mass of O₂ = 31.5 g
Atomic mass Al = 4 x 27 = 108 g
Atomic mass O₂ = 6 x 16 = 96 g
Process
1.- Calculate the limiting reactant
Theoretical proportion Al/O₂ = 108/96 = 1.125
Experimental proportion Al/O₂ = 31.5/31.5 = 1
The limiting reactant is Al because the proportion diminished
2.- Calculate the mass of Al₂O₃
molecular mass Al₂O₃ = (27 x 2) + (16 x 3) = 2(102 g) = 204 g
108 g of Al ---------------------- 204 g of Al₂O₃
31.5 g of Al --------------------- x
x = (31.5 x 204)/108
x = 59.5 g of Al₂O₃
Answer:To calculate the Molarity of a 70 wt. % Nitric Acid the number of moles of HNO 3 present in 1 liter of acid needs to be calculated. Knowing the density of the acid to be 1.413 g/mL, we can calculate the weight of 1 L of 70% HNO 3 to be 1413
Explanation:
Answer
1.60217662 × 10-19 coulombs
Explanation:
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