It seems like the weather made the clothes dry less quickly
Answer is: <span>the volume of water after the solid is added</span> is 4.5 ml.
d(gold) = 8.0 g/cm³; density of gold.
m(gold) = 4 g; mass of gold.
V(gold) = m(gold) ÷ d(gold); volume of gold.
V(gold) = 4 g ÷ 8 g/cm³.
V(gold) = 0.5 cm³ = 0.5 ml.
V(water) = 4.00 ml = 4.00 cm³.
V(flask) = V(gold) + V(water).
V(flask) = 0.5 cm³ + 4 cm³.V = 4.5 cm³.
Answer: 92mg of ethyl alcohol
2 milli molar of ethyl alcohol means 2 milli mole glucose for 1 liter of water. Since we want to make 1L of solution, then the amount of ethyl alcohol needed is: 2 milli mole/l x 1l= = 2 x 10^-3 mole
Ethyl alcohol molecular weight is 46g/mole, then 2 mili mole of glucose is= 2x 10^-3 mole x 46 grams/mole= 92 grams x 10^-3= 92mg
From the stoichiometry of the problem, 2.01 × 10^5 g of zinc phosphate is produced.
<h3>What is volume?</h3>
Volume is the product of width, height and depth. The significant figures of the width, height and depth are 5, 4 and 6 respectively.The volume of the box is; 11.014 × 10^-2 m × 0.2481 m × 523.735 × 10^-3 = 0.01431 m^3 or 14310 cm^3 or 0.5053ft^3.
Density of zinc = 7.140 g / cm3
Volume of zinc = 14310 cm^3
Mass of zinc = 7.140 g / cm3 × 14310 cm^3 = 102 Kg
Moles of Zinc = mass /molar mass = 102 × 10^3/65 g/mol = 1569 moles
There are 195 g of zinc in 386 g zinc phosphate
102 × 10^3 g of Zn will produce x g
x = 102 × 10^3 g × 386 g / 195 g
x = 2.01 × 10^5 g of zinc phosphate
Learn more about stiochiometry: brainly.com/question/9743981
Answer:
The correct answer is
[CH4][H2O]/[CO][H2]3
Option 3 is correct
Explanation:
Step 1: Data given
For the equation aA + bB ⇆ cC + dD
The equilibrium constant is [C]^c * [D]^d / [A]^a*[B]^b
Step 2: Calculate the equilibrium constant Kc
CO+3H2⇌CH4+H2O
Kc = [H2O][CH4] / [CO][H2]³
The correct answer is
[CH4][H2O]/[CO][H2]3
Option 3 is correct
