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Angelina_Jolie [31]
3 years ago
11

Calculate the correct scientific notation. 3.95x10^2/1.5x10^6

Physics
1 answer:
LiRa [457]3 years ago
4 0
<span>This is basically a division equation. Solve the top and the bottom, then divide. The numerator (top part) is 3.95 multiplied by 10 to the second power, which is the same as 3.95 times 100, which is the same as 395. The denominator is 1.5 times 10 to the 6th power, which is the same as 1.5 multiplied by 1,000,000, which is the same as 1,500,000. Dividing 395 by 1,500,000 we get 0.0002633333, or 2.633333e-4, which is another way of putting it.</span>
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A 3.1 kg ball is thrown straight upward with a speed of 18.2 m/s. Use conservation of energy to calculate the maximum height the
spayn [35]

Answer:

h = 16.9 m

Explanation:

When a ball is thrown upward, its velocity gradually decreases, until it stops for a moment, when it reaches the maximum height, while its height increases. Thus, the law conservation of energy states in this case, that:

Kinetic Energy Lost by Ball = Potential Energy Gained by Ball

(0.5)m(Vf² - Vi²) = mgh

h = (0.5)(Vf² - Vi²)/g

where,

Vf = Final Speed of Ball = 0 m/s (Since, ball stops for a moment at highest point)

Vi = Initial Speed of Ball = 18.2 m/s

g = acceleration due to gravity = - 9.8 m/s² ( negative for upward motion)

h = maximum height the ball can reach = ?

Therefore, using values in the equation, we get:

h = (0.5)[(0 m/s)² - (18.2 m/s)²]/(-9.8 m/s²)

<u>h = 16.9 m</u>

4 0
3 years ago
Define the term momentum??
mash [69]
Momentum- most commonly used in physics and STEM, is the quantity of motion of a moving body, measured as a product of its mass and velocity.

6 0
3 years ago
A mass of 3 slugs (this is the English unit of mass, a pound is a force) is attached to a vertical spring with a spring constant
motikmotik

Answer:

equation of motion for the mass is x(t) = e^αt ( C1 cos √{α² - ω²} t + C2 sin  √{α² - ω²} t )

Explanation:

Given data

mass = 3 slugs = 3 * 32.14 = 96.52 lbs

constant k = 9 lbs/ft

Beta = 6lbs * s/ft

mass is pulled =  1 ft below

to find out

equation of motion for the mass

solution

we know that The mass is pulled 1 ft below so

we will apply here differential equation of free motion i.e

dx²/dt² + 2 α dx/dt + ω² x =0     ........................1

here 2 α  =  Beta / mass

so 2 α  = 6 / 96.52

α  = 0.031

α²  = 0.000961         ...............2

and

ω² = k/mass

ω² = 9 /96.52

ω² = 0.093     ..................3

we can say that from equation 2 and 3 that α² - ω²  = -0.092239

this is less than zero

so differential equation is

x(t) = e^αt ( C1 cos √{α² - ω²} t + C2 sin  √{α² - ω²} t )

equation of motion for the mass is x(t) = e^αt ( C1 cos √{α² - ω²} t + C2 sin  √{α² - ω²} t )

3 0
3 years ago
what happens to the average kinetic energy of a gas when the particles of the gas collide against each other at a constant tempe
Rama09 [41]

The average kinetic energy of the gas would also be constant since the temperature of the gas is not changing.

<h3>What happens to the average kinetic energy?</h3>

The kinetic energy is the energy of the particle that is motion. We know that the kinetic energy of the gas is proportional to the temperature of the gas. As the temperature increases, the kinetic energy of the particles of the gas increases.

Now we can see that the gas has been maintained at a constant temperature and a constant volume and that the particles of the gas collide with each other. This implies that the average kinetic energy of the gas would also be constant since the temperature of the gas is not changing.

Learn more about average kinetic energy:brainly.com/question/1599923

#SPJ1

4 0
2 years ago
The CERN particle accelerator is circular with a circumference of 7.0 km.
Contact [7]

Answer:

a_c=2.0196\times 10^{13}\ m/s^2

F=3.37273\times 10^{-14}\ N

Explanation:

m = Mass of proton = 1.67\times 10^{-27}\ kg

v = Speed of proton = 0.5c = 0.5\times 3\times 10^8=1.5\times 10^8\ m/s

Circumference of the colider is 7 km

P=2\pi r\\\Rightarrow r=\frac{P}{2\pi}\\\Rightarrow r=\frac{7000}{2\pi}\ m

a_c=\frac{v^2}{r}\\\Rightarrow a_c=\frac{\left(1.5\times 10^8\right)^2}{\frac{7000}{2\pi}}\\\Rightarrow a_c=2.0196\times 10^{13}\ m/s^2

Centripetal acceleration is 2.0196\times 10^{13}\ m/s^2

F_c=ma_c\\\Rightarrow F_c=1.67\times 10^{-27}\times 2.0196\times 10^{13}\\\Rightarrow F=3.37273\times 10^{-14}\ N

Force on protons is 3.37273\times 10^{-14}\ N

8 0
4 years ago
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