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4 years ago

The CERN particle accelerator is circular with a circumference of 7.0 km.

Physics

1 answer:

Contact [7]4 years ago

8 0

Answer:

$a_c=2.0196\times 10^{13}\ m/s^2$

$F=3.37273\times 10^{-14}\ N$

Explanation:

m = Mass of proton = $1.67\times 10^{-27}\ kg$

v = Speed of proton = 0.5c = $0.5\times 3\times 10^8=1.5\times 10^8\ m/s$

Circumference of the colider is 7 km

$P=2\pi r\\\Rightarrow r=\frac{P}{2\pi}\\\Rightarrow r=\frac{7000}{2\pi}\ m$

$a_c=\frac{v^2}{r}\\\Rightarrow a_c=\frac{\left(1.5\times 10^8\right)^2}{\frac{7000}{2\pi}}\\\Rightarrow a_c=2.0196\times 10^{13}\ m/s^2$

Centripetal acceleration is $2.0196\times 10^{13}\ m/s^2$

$F_c=ma_c\\\Rightarrow F_c=1.67\times 10^{-27}\times 2.0196\times 10^{13}\\\Rightarrow F=3.37273\times 10^{-14}\ N$

Force on protons is $3.37273\times 10^{-14}\ N$

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A curent-carrying 2.0-cm long segment of wire is inside a long solenoid adius - 40 cm - 800 turns/m, current - 50 mA). The wire

klasskru [66]

Answer:

The value is $F_{max} = 12 \muN$

Explanation:

From the question we are told that

The length is $l = 2.0 \ cm = 0.02 \ m$

The radius of the the solenoid is $r =40 \ cm$

The number of turns per meter is $N = 800 \ turns / m$

The current through the solenoid is $I = 50 \ mA = 50*10^{-3} \ A$

The current through the segment is $I_s = 12 \ A$

Generally the magnetic force is mathematically represented as

$F = B * I_s l sin(\theta)$

At maximum $\theta = 90^o$

$F_{max} = B * I_s l$

Here B is the magnetic field is mathematically represented as

$B = \mu_o * N * I$

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} N/A^2$

$B = 4\pi * 10^{-7} * 800 *50*10^{-3}$

=> $B = 5.0272 *10^{-5} \ T$

$F_{max} = 5.0272 *10^{-5} * 12 * 0.02$

$F_{max} = 1.2 *10^{-5}$

$F_{max} = 12 \muN$

4 0

3 years ago

Three balls are kicked from the ground level at some angles above horizontal with different initial speeds. All three balls reac

astra-53 [7]

Answer:

They all hit at the same time

Explanation:

Let the time of flight is T.

The maximum height is H and the horizontal range is R.

The formula for the time of flight is

$T=\frac{2uSin\theta }{g}$ ..... (1)

Te formula for the maximum height is

$H=\frac{u^{2}Sin^{2}\theta }{2g}$ .... (2)

From equation (1) and (2), we get

$\frac{T^{2}}{H}=\frac{\frac{4u^{2}Sin^{2}\theta }{g^{2}}}{\frac{u^{2}Sin^{2}\theta }{2g}}$

$\frac{T^{2}}{H}=\frac{8}{g}$

$T=\sqrt{\frac{8H}{g}}$

here, we observe that the time of flight depends on the maximum height and according to the question, the maximum height for all the three balls is same so the time of flight of all the three balls is also same.

8 0

3 years ago

Why don't we use more renewable energy sources

sattari [20]

Answer:

Renewable energy sources 1.Cost more then nonrenewable resources and 2.Are so far not as reliable as nonrenewable energy.

Explanation:

4 0

3 years ago

Read 2 more answers

An inductor is connected to an AC generator. As the generator's frequency is increased, the current in the inductor A. Increases

Luda [366]

Answer:

B) Decrease

Explanation:

Resistance offered due to inductor in any AC circuit is given as

$X_L = \omega L$

here we know that

$\omega$ = angular frequency

$\omega = 2\pi f$

now by ohm's law we know that

$i = \frac{V}{X}$

here we have

$i = \frac{V}{\omega L}$

so current is inversely depends on the frequency of AC

so if frequency is increased then the current will decrease

6 0

3 years ago

Pls help :/

vodomira [7]

Answer:

Gravitational attraction of the sun.

Explanation:

Gravity is an attractive force. Any two masses will exert an attractive force on the other according to Newton's law of universal gravitation. The more massive the objects, the stronger the force. The sun, as you can probably guess, is pretty massive - 330,000 times more than Earth, and 1,048 time more than Jupiter, our solar system's largest planet. Just like man-made satellites around Earth, the planets in our solar system are constant process of "falling" around the sun, locked in their orbits by its mass, but slowing dramatically in their orbital velocity the further away they are.

6 0

3 years ago