The empirical and molecular formula : C₂₁H₂₂N₂O₂
<h3>Further explanation</h3>
Given
The percent composition of an unknown substance is 75.42% Carbon, 6.63 % Hydrogen,
8.38 % Nitrogen, and 9.57 % Oxygen
Required
The empirical and molecular formula
Solution
C : 75.42 : 12 = 6.285
H : 6.63 : 1 = 6.63
N : 8.38 : 14 = 0.599
O : 9.57 : 16 = 0.598
Divide by 0.598
C : H : N : O = 10.5 : 11 : 1 : 1 = 21 : 22 : 2 : 2
The empirical formula : C₂₁H₂₂N₂O₂
(C₂₁H₂₂N₂O₂)n = 334
(334)n=334
n = 1
Answer:
invertibrate
Explanation:
if I recall it is because they have no spine.
He would hv concluded that the ratio of the masses of nitrogen to sulphur is in the ratio 1 :3
By calculating the answer
Answer:
17.6% is the percentage error
Explanation:
The percentage error is used to determine accuracy of a measurement (That is, how closely is the measure to the real or theoretical value). The equation is:
|Measure - Real| / Real * 100
In the problem, the measure was 22.7cm³ and real value is 19.3cm³. Solving for percentage error:
|22.7cm³ - 19.3cm³| / 19.3cm³ × 100
<h3>17.6% is the percentage error</h3>
