The less soluble salt : PbCl₂
<h3>Further explanation</h3>
Given
0.1 M NaCl
Required
The less soluble salt
Solution
If we see from the answer option, the salt that is more difficult to dissolve in NaCl is PbCl₂ because it has the same ion (Cl)
When PbCl₂ is dissolved in water, ionization will occur
PbCl₂ ⇒ Pb²⁺+ 2Cl⁻
So, when dissolved in NaCl, NaCl itself will be ionized
NaCl ⇒ Na⁺ + Cl⁻
Based on the principle of equilibrium, the addition of an ion (one of the ions is enlarged), the reaction will shift towards the ion that was not added. In addition to this Cl ion, the reaction will shift to the left so that the solubility of PbCl₂ will decrease (the reaction to the right decreases)
The normality of the H₂SO₄ that reacted with 25cc of 5 % NaOH solution is 1.1 N.
<h3>What is the molarity of 5% NaOH?</h3>
The molarity of 5% NaOH is 1.32 M
25 cc of NaOH neutralized 30cc of H₂SO₄ solution.
Equation of reaction is given below:
- 2 NaOH + H₂SO₄ ---> Na₂SO₄ + 2 H₂O
Molarity of H₂SO₄ = 1.32 x 1 x 25/(30 x 2) = 0.55 M
- Normality = Molarity × moles of H⁺ ions per mole of acid
moles of H⁺ ions per mole of H₂SO₄ = 2
Normality of H₂SO₄ = 0.55 x 2 = 1.1 N
In conclusion, the normality of an acid is determined from the molarity and the moles of H⁺ ions per mole of acid.
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Moles = mass / molar mass
molar mass of O2 is 32
therefore moles = 72/32
= 2.25 moles
C. PH3 represents a compound commonly known as phosphine, whose IUPAC name is phosphorus trihydride.
<h3>What type of bond is PH3?</h3>
The electronegativity of PH3 found in the Periodic Table of the Period attracts covalent electron pairs and creates covalent bonds. However, because the electrons are not bound, asymmetrical rate distribution occurs. Therefore, PH3 is a polar molecule with a non-polar covalent bond and currently has no polar bond.
<h3 /><h3>What defines a covalent bond?</h3>
A covalent bond consists of sharing one or more electron pairs between two atoms. These electrons are attracted to two nuclei at the same time. Covalent bonds are formed when the difference in electronegativity between two atoms is too small for electron transfer to form ions.
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