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g100num [7]
3 years ago
15

Two species of frog mate in the same pond. One breeds in early summer and one in late summer. This is an example of what kind of

reproductive isolation?
A. pre-zygotic, behavioral isolation
B. pre-zygotic, temporal separation
C. pre-zygotic, ecological separation
D. post-zygotic, temporal separation
E. post-zygotic, ecological separation
Chemistry
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

Pre-zygotic, temporal separation

Explanation:

Reproductive isolation mechanism is of two types:

  • Prezygotic mechanism
  • Postzygotic mechanism

Prezygotic mechanism isolation occurs before fertilization and helpful in preventing formation of fertile offspring.

In frog external fertilization occurs. In the external fertilization, eggs and sperms are released in water and fertilization occur outside the water.

Prezygotic isolating mechanisms may include behavioral isolation, temporal isolation, mechanical isolation, gametic isolation and habitat isolation.

Temporal separation in reproduction is the sexual activity in the same geographical range but in different periods.

Therefore, the given reproductive isolation is pre-zygotic, temporal separation.

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S^{2-} is having lowest oxidation number of sulphur in teh options given. The oxidation number is -2.

The correct option is E.

Explanation:

S^{2-} have oxidation number of -2, which is lowest in all the options given.

In the given examples S_{8} will have oxidation number zero because it is in elemental form. In the rules for oxidation number it is given that any element in free state has its oxidation number zero.

All other options are in compound form as:

SO_{3} ^{2-} =  oxidation number is +4. It is calculated as oxygen having O.N of -2,

The charge on the atom is -2, so sum of the oxidation numbers of all the elements should be equal to -2.

x+3(-2)= -2

x = 4

SO_{4} ^{2-}= The charge on the atom is -2, so sum of the oxidation numbers of all the elements should be equal to -2.

x +4(-2) = -2

x = +6

S_{2}O_{3^{2-} }

The charge on the atom is -2, so sum of the oxidation numbers of all the elements should be equal to -2.

2x + 3(-2) = -2

2x = 4

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