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frutty [35]
3 years ago
12

What is the (OH-) in a solution with a pOH of 6.48

Chemistry
1 answer:
inn [45]3 years ago
3 0
Through manipulation of equations, we are able to obtain the equation:

-pOH= log [ OH^{-}]

Then we can transform the equation into:

[ OH^{-}]= 10^{-pOH}

Then we are able to plug in the pOH and directly get [OH-]:

[ OH^{-}] = 10^{-6.48}

[ OH^{-}]=3.31* 10^{-7} M
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