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klemol [59]
4 years ago
5

Devon is trying to find the unit price on a 6-pack of drinks on sale for $2.99. his sister says that at that price,each drink wo

ykd cost just over $2.00 . is she correct,and how do you now? if she is not, how would devon's sister find the correct price?
Mathematics
1 answer:
tresset_1 [31]4 years ago
6 0
It is not true

6pack = 6 pieces ? 

6 pieces for $2.00 = $12   not $2.99

Devon should divide $2.99/6  ~~  $0.49


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The Baker formula estimates the maximum heart rate, in beats per minute, of a person who is
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Answer:

For a=16, the Maximum Heart Rate is 188 Beats Per Minute.

Step-by-step explanation:

<em>To begin, we know that the formula:</em>

b(a)=200-0.75a    Eqn(1).

<u>is equivalent to a linear equation of algebraic form denoted as:</u>

y=k+mx                  Eqn(2)

<em>as such that  Eqns (1) and (2) relate as follow:</em>

y ⇔ b(a): denoting our Dependent Variable, in this case <em>Max. Heart Rate in Beats Per Minute</em>

x ⇔ a: is our Independent Variable<em>, </em>in this case the <em>Age of the Person</em>

m ⇔ 0.75: denoting the<em> Rate of Change of the Age.</em>

k ⇔ 200: denoting our <em>Constant.</em>

Now in the question our value of b(a) is given as 188 beats per minute, which by plugging in Eqn(1) gives:

200-0.75a=188

from which we can solve to obtain the value of a as follow:

-0.75a=188-200          Gather similar terms on each side

-0.75a=-12\\                   Simplify

a=\frac{-12}{-0.75}                           Solve for a

a=16

Which tells us that at the Age of 16, the Max. Heart Rate is 188 Beats Per Minute.

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DaniilM [7]
Yes that great hope that helped :)
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5+5+5+5+5+5+5+5+5+5+5+5
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}

Or, if you mean (r+3Q)/h=t:

\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}

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