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Rama09 [41]
3 years ago
15

Carol is one-sixth of an inch taller than dave.dave is fifty-eight and a half inches tall.how tall is carol

Mathematics
1 answer:
katrin2010 [14]3 years ago
5 0
C=1/6 of x
D=55/1/2
1/6 of 111/2=110.167
55.08
=55 inches
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Anyone??? need some help huys:)
atroni [7]

Slope-intercept form:

y = mx + b        "m" is the slope


First i would isolate the "y" in the equation.

2x + y = 4       Subtract 2x on both sides

2x - 2x + y = 4 - 2x

y = 4 - 2x    or     y = -2x + 4

The given line's slope is -2.


For lines to be perpendicular, their slopes have to be the opposite/negative reciprocals (flipped sign and number)

For example:

slope is 2

perpendicular line's slope is -1/2

slope is -2/3

perpendicular line's slope is 3/2


The given line's slope is -2, so the perpendicular line's slope is 1/2.

The 3rd option is your answer

4 0
3 years ago
A) 20 milligrams of the drug lincomycin is to be given for each kilogram of a person's weight the drug is be mixed with 250 cc o
krok68 [10]

Answer:

you need to convert pounds to kilograms. 196 pounds is 88.904 kilograms. The directions tell you that 20 milligrams of the drug is to be administered for each kilogram of a person's weight. Now you need to multiply 88.904 by 20. That should give you 1778.08 milligrams of lincomycin. You would then mix 250 cc's of saline solution to the 1778.08 milligrams of lincomycin; but I think its just asking you how much lincomycin to administer.

at what rate per minute should the 250 cc solution be adminstered

4 0
3 years ago
While walking between gates at an airport, you notice a child running along a moving walkway. Estimating that the child runs at
tekilochka [14]

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

<h3>How to estimate the speed of the moving walkway relative to the airport terminal?</h3>

Let x be the speed of the walkway.

(2.8 + x) = speed of child moving in direction of the walkway

(2.8 - x) =  speed of child moving against the direction of the walkway

Travel time = distance/speed

Travel time of child moving in direction of walkway = 23/(2.8+x)

Total elapsed time given = 29s

23/(2.8 + x)+ 23 / (2.8-x) = 29

LCD = (2.8 + x)(2.8 - x)

23(2.8 - x) + 23(2.8 + x) = 29(2.8 + x)(2.8 -x)

simplifying the equation, we get

23*2.8-23x+23*2.8+23x=29(2.8^2-x^2)

23(2.8+2.8)/29=2.8^2-x^2

x^2=(2.8)^2-(23*5.6)/29)=3.4

x=\sqrt{3.4}=1.84m/s

Speed of walkway = 1.84 m/s

The speed of the moving walkway relative to the airport terminal exists at 1.84 m/s.

To learn more about Speed refer to:

brainly.com/question/4931057

#SPJ4

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2 years ago
Please help!!!! Chris is a fitness instructor.
dmitriy555 [2]

Answer:

i think its d

Step-by-step explanation:

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What might your scatter plot depict
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It is supposed to predict the points, or the correlational relationship between variables.

Step-by-step explanation:

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