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RUDIKE [14]
2 years ago
12

Evaluate a^2b^2? when a = 5 and b = 3.

Mathematics
1 answer:
kvasek [131]2 years ago
5 0

Answer:

D) 7

Step-by-step explanation:

a^{2} -2b^{2}

a=5

b=3

\left(5\right)^2-2\left(3\right)^2

Calculate 5 to the power of 2 and get 25:-

25-2\times 3^{2}

Calculate 3 to the power of 2 to get 9 and then multiply 2 and 9 to get 18:-

25-18

=7

<u>OAmalOHopeO</u>

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Find the area a of the triangle whose sides have the given lengths. a = 20, b = 15, c = 25 a =?
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The area of a triangle with sides a = 20, b = 15, and c = 25 is 150.

The sides of the triangle are given as a = 20, b = 15, and c = 25.

We will use Hero's formula to find the area of this triangle.

<h3>What is Heron's formula?</h3>

It is a three-face polygon that consists of three edges and three vertices.

We use Heron's formula to find the area of a triangle with 3 sides:

Herons formula:

Area of a triangle =  \sqrt{s(s-a)(s-b)(s-c)}\\

Where a, b, and c are sides of a triangle.

And s = semi perimeter of a triangle.

s = \frac{a+b+c}{2}

If the sum of two sides of a triangle is greater than the third side of a triangle then the sides of a triangle are true.

Let the given sides be:

a = 20, b = 15 and c = 25.

(20 + 15) > 25

(20 + 25) > 15

(15 + 25) > 20 so the given sides are true.

Now,

Semi perimeter of the triangle:

s = (a+b+c) / 2

s = (20+15+25) / 2

s = 60 / 2

s = 30

Putting s = 30 in the area of the triangle.

we get,

Area of the triangle = \sqrt{s(s-a)(s-b)(s-c)}\\

Area of the triangle = \sqrt{30(30-20)(30-15)(30-25)}\\\\\sqrt{30\times10\times15\times5}\\\\\sqrt{22500}\\\\150

Thus, the area of a triangle is 150.

Learn more about the Area of triangles here:

brainly.com/question/11952845

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