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RUDIKE [14]
2 years ago
12

Evaluate a^2b^2? when a = 5 and b = 3.

Mathematics
1 answer:
kvasek [131]2 years ago
5 0

Answer:

D) 7

Step-by-step explanation:

a^{2} -2b^{2}

a=5

b=3

\left(5\right)^2-2\left(3\right)^2

Calculate 5 to the power of 2 and get 25:-

25-2\times 3^{2}

Calculate 3 to the power of 2 to get 9 and then multiply 2 and 9 to get 18:-

25-18

=7

<u>OAmalOHopeO</u>

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What is the answer to<br> -2a-9=6a+15
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Answer:

a=-3

Step-by-step explanation:

-2a-9=6a+15

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3 years ago
Working together, it takes Sam, Jenna, and Francisco two hours to paint one room. When Sam works alone, he can paint one room in
lutik1710 [3]

Answer:  12 hours

Step-by-step explanation:

Given : Working together, it takes Sam, Jenna, and Francisco two hours to paint one room.

When Sam works alone, he can paint one room in 6 hours. When Jenna works alone, she can paint one room in 4 hours.

Let 't' be the time taken by Francisco to paint one room on his own.

Then , we have

Rate of work of  Sam +Rate of work of Jenna + Rate of work of  Francisco =Rate of work they all do together

\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{t}=\dfrac{1}{2}

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{1}{6}+\dfrac{1}{4})

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{4+6}{24})

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-\dfrac{10}{24}

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-\dfrac{5}{12}

i.e.  \dfrac{1}{t}=\dfrac{6-5}{12}

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i.e. t= 12

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8 0
3 years ago
A circle has its center at (0,0) and passes through the point (0,9). What is the standard equation of the circle?
Alexxandr [17]

Answer:

x^2+y^2=9^2

Step-by-step explanation:

The standard equation of a circle is:

(x-h)^2+(y-k)^2=r^2

Where the center of a circle is (h,k) and r is the radius of the circle.  In this case because a circle is equidistant from the center and we have a point where it passes through 9 that means that the radius is 9.  However, since the standard equation states that we must write r in the form of r^2 this means that r^2=9^2.  Therefore by plugging in the values we have:

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7 0
3 years ago
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