All categories

3 years ago

ASAP PLEASEEEEEEEE

Mathematics

1 answer:

shtirl [24]3 years ago

5 0

Answer:

x = -122/13 OR 9.3846

Step-by-step explanation:

First, take a look at the second equation. Add 8x to the other side.

-7y= 8x -18

Then, divide by -7 to get a regular "y=" equation.

y= 8/7x -18/7

Move on the the first equation. Let's get "y" by itself. Add 3x to the other side.

y= 3x +15

Considering both equations are equal to Y, set them equal ( except the "y" part )

8/7x - 18/7 = 3x + 15

Multiply all by seven so that there are no fractions.

8x - 18 = 21x + 105

Subtract 8x from both sides.

-17 = 13x + 105

Subtract 105 from both sides.

-122 = 13x

Divide by 13 on both sides.

x = 9.3846

Or if you don't want decimals, just say x = -122/13

Quick Note: I made a mistake. I had looked at the second equation at -18. The answer is incorrect but the method of solving is correct. Also, make sure to plug in the value of x to get Y.

You might be interested in

Can anyone help me on this I would appreciate it

kaheart [24]

Answer:

Step-by-step explanation:

Triangle=180

180-90 (RA) = 90

90-41= 39

(2x+11)=39

2x=28

x=14

3 0

2 years ago

Read 2 more answers

please give me the explanation for this question, been on it for like 3 hours and can't get the answer

g100num [7]

Answer: your answer is correct I don't understand why you can't get it

I got the exact same answer

4 0

3 years ago

Read 2 more answers

The area of a rectangular pool is 6072 m(squared)

lesya [120]

Answer:

88 m

Step-by-step explanation:

A=L×w

Where A=6072 m squared, w=69 m

6072=L×69

L=6072/69

L=88 m

3 0

3 years ago

7. Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

morpeh [17]

Hey there!

Use the quadratic formula to find the solution(s). x² + 2x - 8 = 0

Answer :

x = -4 or x = 2 ✅

Explanation :

Quadratic formula : ax² + bx + c = 0 where a ≠ 0

The number of real-number solutions (roots) is determined by the discriminant (b² - 4ac) :

If b² - 4ac > 0 , There are 2 real-number solutions

If b² - 4ac = 0 , There is 1 real-number solution.

If b² - 4ac < 0 , There is no real-number solution.

The roots of the equation are determined by the following calculation:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

Here, we have :

a = 1
b = 2
c = -8

1) Calculate the discriminant :

b² - 4ac ⇔ 2² - 4(1)(-8) ⇔ 4 - (-32) ⇔ 36

b² - 4ac = 36 > 0 ; The equation admits two real-number solutions

2) Calculate the roots of the equation:

▪️ (1)

$x_1 = \frac{ - b - \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ x_1 = \frac{ - 2 - \sqrt{36} }{2(1) } \\ \\ x_1 = \frac{ - 2 - 6}{2} \\ \\ x_1 = \frac{ - 8}{2} \\ \\ \blue{\boxed{\red{x_1 = -4}}}$

▪️ (2)

$x_2 = \frac{ - b + \sqrt{ {b}^{2} - 4ac } }{2a} \\ \\ x_2 = \frac{ - 2 + \sqrt{36} }{2(1)} \\ \\ x_2 = \frac{ - 2 + 6}{2} \\ \\ x_2 = \frac{4}{2} \\ \\ \red{\boxed{\blue{x_2 = 2}}}$