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ss7ja [257]
2 years ago
7

Each course at a community college is worth 1 or 2 credits. A group of students is taking a total of 16 courses that are worth a

total of 28 credits. How many​ 1-credit courses are being​ taken? How many​ 2-credit courses are being​ taken?
Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
6 0

Answer:

They  are taking 12 2 credit courses

The are taking 4  1 credit courses

Step-by-step explanation:

x = 1 credit courses

y = 2 credit courses

The number of courses is 16

x+y = 16

The number of credits is 28 so multiply the course by the number of credits

1x+2y=28

Subtract the first equation from the second equation

x+2y =28

-x-y=-16

-----------------

y = 12

They  are taking 12 2 credit courses

We still need to find the 1 credit courses

x+y = 16

x+12= 16

Subtract 12 from each side

x-12-12 = 16-12

x =4

The are taking 4  1 credit courses

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a. the cost of a call for six minutes is 0.70.

b.the cost of a 14-minute call is 2.62.

c.the cost of a 9 ½2-minute call is 1.66.

<h3>How to find the cost of each call ?</h3>

given that

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c(m) = 0.70 when m<=6

c(m) = 0.70+ 0.24(m-6) when m>6 & m is an integer

c(m) = 0.70+0.24((m-6)+1) when m>6 & m is not an integer.

a. to find the cost of a call for six minutes.

already given that c(m) =0.70 when m=6.

Therefore, the cost of a call for six minutes is 0.70.

b. to find the cost of a 14-minute call.

according to given information

c(14) = 0.70 + 0.24(m - 6) \\ c(14) = 0.70 + 0.24(14 \: - 6)  \\c(14) = 0.70 + (0.24 \times 14) - (0.24 \times 6) \\c(14) = 0.70 + (3.36 - 1.44) \\ c(14) = 0.70 + 1.92 \\ c(14) = 2.62

Therefore,the cost of a 14-minute call is 2.62.

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according to given information

c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 \frac{1}{2} 2 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24((9 - 6) + 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(3+ 1) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.24(4) \\ c(9  \frac{1}{2} 2) = 0.70 + 0.96 \\ c(9  \frac{1}{2} 2) = 1.66

Therefore,the cost of a 9 ½2-minute call is 1.66.

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