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Umnica [9.8K]
3 years ago
10

Max received a gift certificate at the Book Barn, so he decided to give away the books that he read. He divided the books evenly

among three friends. Each friend got 8 books. Write and solve an equation to find how many books Max gave away.
Mathematics
1 answer:
tia_tia [17]3 years ago
3 0

Answer:

24 books

Step-by-step explanation:

So if he gave 8 books each to 3 friends, we can call the total books he gave away, B, and the equation will look like this:

B = 3(8)

Now, we just combine the like terms:

B = 24 books.

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WILL GIVE BRAINLIEST 2 hours x 47 mph please show work for brainliest
gtnhenbr [62]

Answer:

2 hours * (47 miles / hour) = 94 miles

multiply the value in miles per hour by the conversion factor '1.609344'.

So, 2.2 miles per hour = 2.2 × 1.609344 = 3.5405568 kilometers per hour.

Step-by-step explanation:

7 0
3 years ago
Graph f(x) = 2x^4+3 <br> let x = 0, 1, and 2.<br> please show your work
mestny [16]
Sub those points for x
f(x) is the y

(x,y)

so for x=0
f(0)=2(0)^4+3
f(0)=0+3
f(0)=3
(0,3) is a opint

for x=1
f(1)=2(1)^4+3
f(1)=2(1)+3
f(1)=2+3
f(1)=5
(1,5) is another point

for x=2
f(2)=2(2^4)+3
f(2)=2(16)+3
f(2)=32+3
f(2)=35
(2,35) is another point


points are
(0,3)
(1,5)
(2,35)
3 0
3 years ago
Find the next number in the pattern: 3 5 11 6 7 5 14 8 12 ? Explain why
stepan [7]

Answer:

5–3 = 2

8–5 = 3

12–8 = 4

17–12 = 5

x-17 should be 6, hence x = 6+17 = 23.

Step-by-step explanation:

7 0
3 years ago
The sum of the first natural number and 0 is 1, the sum of the first two natural numbers and 0 is 3, the sum of the first three
Kitty [74]
The sum of the first n natural numbers and 0=
n*(n+1)/2
8 0
3 years ago
Read 2 more answers
Factorize this expression completely <br>using (a-b)² formula<br>3a²- 36a + 108​
Novosadov [1.4K]

Answer:

3a^2 - 36a + 108  = (\sqrt{3}a - 6\sqrt{3} )^2

Step-by-step explanation:

3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2

so, a = \sqrt{3}  a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}

Therefore ,

3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2  = (\sqrt{3}a - 6\sqrt{3} )^2

6 0
3 years ago
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