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3 years ago

Solve by using substitution . SHOW YOUR WORK. 3х + y = –17 бx — бу = –18

Mathematics

2 answers:

lilavasa [31]3 years ago

4 0

Step-by-step explanation:

1. 3x+y+17=0

2.x-y+3=0

Sorry mam I use mental math

weqwewe [10]3 years ago

4 0

Answer: X = —5 and Y = —2

Step-by-step explanation: What we have is a pair of simultaneous equations;

3X + Y = —17 —————-(1)

6X — 6Y = —18 ————(2)

We shall use the substitution method as instructed. Looking at equation (1),

We shall make Y the subject of the equation, hence

Y = —17 —3X

We shall now substitute for the value of Y into equation (2)

6X — 6Y = —18

6X — 6(—17 —3X) = —18

6X + 102 + 18X = —18

By collecting like terms we now have

24X = —18 —102

(Note that when a positive value crosses to the other side of the equation it becomes negative and vice versa)

24X = —120

Divide both sides of the equation by 24

X = —5

Having calculated the value of X as —5, we can now calculate Y as follows

From equation (1)

3X + Y = —17

3(—5) + Y = —17

—15 + Y = —17

Add 15 to both sides of the equation

—15 + 15 + Y = —17 + 15

Y = —2

Therefore, X = —5 and Y = —2

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3 years ago

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3 years ago

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3 years ago

What is the slope of the line passing through the points (2, −5) and (4, 1)? 2 −4/5 5/4 3

satela [25.4K]

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3 0

3 years ago

The volume of a sphere is two-thirds of a cylinder. What is the volume of a cylinder that has the same diameter as a sphere with

sattari [20]

Answer:

$V_2= \frac{28}{3} u^3$

Step-by-step explanation:

Given

Represent the volume of the cylinder with V1 and the volume of the sphere with V2

So, from the first statement: we have:

$V_2 =\frac{2}{3}V_1$

and

$V_1 = 14u^3$

To solve for $V_2$ , we simply substitute $14u^3$ for $V_1$ in $V_2 =\frac{2}{3}V_1$

$V_2 =\frac{2}{3}V_1$

$V_2= \frac{2}{3} * 14u^3$

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Hence, the volume of the sphere is $\frac{28}{3} u^3$

5 0

3 years ago