Answer:
Interval of 50 on both axis
Step-by-step explanation:
Given
There are several ways to do this, but I will use the observation method, since the dataset is small.
Considering the x-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the x-axis
Considering the y-coordinates
Each element of the data set is a multiple of 50.
Hence, an interval of 50 can be used on the y-axis
<em>So, an interval of 50 can be used on both axes</em>
Answer:
y = x + 15
Step-by-step explanation:
If two lines are perpendicular to each other, they have opposite slopes.
The first line is y = - x - 2. Its slope is -1. A line perpendicular to this will have a slope of 1.
Plug this value (1) into your standard point-slope equation of y = mx + b.
y = 1x + b or y = x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (-5, 10). Plug in the x and y values into the x and y of the standard equation.
10 = (-5) + b
Simplify.
10 = -5 + b
Now, add 5 to both sides to isolate b.
15 = b
Plug this into your standard equation.
y = x + 15
This equation is perpendicular to your given equation (y = -x - 2) and contains point (-5, 10)
Hope this helps!
